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anonymous

  • one year ago

What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4?

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  1. anonymous
    • one year ago
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    @campbell_st

  2. anonymous
    • one year ago
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    sorry i forgot your name :) so i couldn't tag you

  3. jdoe0001
    • one year ago
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    well hmmm \(\bf f(x)=\cfrac{2x^2+5x-12}{x+4}\) anyway to factor say \(\bf 2x^2+5x-12?\)

  4. anonymous
    • one year ago
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    (x+4)(2x-3)

  5. jdoe0001
    • one year ago
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    hmm,, right so \(\bf \cfrac{2x^2+5x-12}{x+4}\implies \cfrac{\cancel{(x+4)}(2x-3)}{\cancel{(x+4)}}\) so.. that's the graph, just a LINEar function, thus is just a line now, where is it discontinued, where does the line have a gap?

  6. anonymous
    • one year ago
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    (-4,-11)

  7. jdoe0001
    • one year ago
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    so.. let's us check if say we set x = -4 so...on the original equation we'd have \(\bf \cfrac{2x^2+5x-12}{x+4}\qquad {\color{brown}{ x=4}}\implies \cfrac{2{\color{brown}{ -4}}^2+5{\color{brown}{ -4}}-12}{{\color{brown}{ -4}}+4}\) the denominator turns to 0, thus making the fraction undefined, thus the gap at that value, when x= -4

  8. anonymous
    • one year ago
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    ok. I agree.

  9. jdoe0001
    • one year ago
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    :)

  10. anonymous
    • one year ago
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    so the zero would be at 3/2, and 0? And discontinuity would be (-4,-11)

  11. anonymous
    • one year ago
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    3

  12. anonymous
    • one year ago
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    ??

  13. jdoe0001
    • one year ago
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    the zero is at x= 3/2 and the discontinuity is at x = -4

  14. anonymous
    • one year ago
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    Gotcha :) Thanks once again

  15. jdoe0001
    • one year ago
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    yw

  16. anonymous
    • one year ago
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    Don't kill me but I have another, I'll tag u again :)

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