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anonymous

  • one year ago

What is the discontinuity and zero of the function f(x) = the quantity of 2 x squared plus 5 x minus 12, all over x plus 4?

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  1. anonymous
    • one year ago
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    @jdoe0001

  2. jdoe0001
    • one year ago
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    ahemm didn't you just do that one?

  3. anonymous
    • one year ago
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    Whoops hold on

  4. anonymous
    • one year ago
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    What is the discontinuity of the function f(x) = the quantity of x squared minus 4 x minus 12, all over x plus 2?

  5. anonymous
    • one year ago
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    |dw:1436224952239:dw|

  6. anonymous
    • one year ago
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    is it 6,0

  7. jdoe0001
    • one year ago
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    \(\bf f(x) = \cfrac{x^2-4x-12}{x+2}\to \cfrac{(x-6)\cancel{(x+2)}}{\cancel{(x+2)}} \\ \quad \\ -----------------------\\ \cfrac{x^2-4x-12}{x+2}\qquad {\color{brown}{ x=-2}}\implies \cfrac{x^2-4x-12}{{\color{brown}{ -2}}+2}\implies \cfrac{x^2-4x-12}{0}\)

  8. jdoe0001
    • one year ago
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    whenever the value of "x", makes the denominator 0, it makes the fraction undefined, and that means that's where the graph has a gap or is discontinued

  9. anonymous
    • one year ago
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    ok, i understand

  10. anonymous
    • one year ago
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    was i wrong?

  11. jdoe0001
    • one year ago
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    well, once the x+2 gets cancelled all you're left with is x-6 or x-6 = 0 x = 6 <-- solution, or x-intercept

  12. anonymous
    • one year ago
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    ok.

  13. anonymous
    • one year ago
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    :) thanks once again

  14. jdoe0001
    • one year ago
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    yw

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