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anonymous
 one year ago
Which graph represents the function of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 65?
anonymous
 one year ago
Which graph represents the function of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 65?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i meant using graphing technology, and then tell where the point of discontinuity is on the graph

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or \(\bf \cfrac{4x^24x8}{2x+2}\implies \cfrac{4(x^2x2)}{2(x+1)}\implies \cfrac{4\cancel{(x+1)}(x2)}{2\cancel{(x+1)}} \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes so it would be 2(x2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeap, that's the line 2(x2) http://fooplot.com/#W3sidHlwZSI6MCwiZXEiOiIyKHgtMikiLCJjb2xvciI6IiMyNjM3RUQifSx7InR5cGUiOjEwMDAsIndpbmRvdyI6WyItOC4yMTg3NDk5OTk5OTk5OTYiLCI4LjAzMTI0OTk5OTk5OTk5NiIsIi0zLjkzNzQ5OTk5OTk5OTk5ODIiLCI2LjA2MjQ5OTk5OTk5OTk5OCJdfV0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0btw, you can zoom in/out on those graphs, by using the middlemouse button

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would the point go on (1,6) or (1,2)??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0graph of 2 x minus 4, with discontinuity at negative 1, negative 6 OR graph of 2 x minus 4, with discontinuity at 1, negative 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well... hold the mayo... notice, if x = 1 the denominator turns 0

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\bf \cfrac{4x^24x8}{2x+2}\qquad {\color{brown}{ x=1}}\implies \cfrac{4x^24x8}{2({\color{brown}{ 1}})+2}\implies \cfrac{4x^24x8}{0}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 1,6 is not a point on the line

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0If I ever have another question, I'll make sure to tag you :) Bye!!
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