how do i find the angle meaurement of ABC and ACB on a triangle.

- anonymous

how do i find the angle meaurement of ABC and ACB on a triangle.

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- schrodinger

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- jdoe0001

got pic?

- Setsuna-Yuregeshi

What information do they give you?

- anonymous

heres the triangle.

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## More answers

- Setsuna-Yuregeshi

That's all they give you?
(I'm just asking)

- jdoe0001

what section is this meant to cover? are you doing trig? law of sines or cosines?

- anonymous

just congruency and geometry. im really lost with this

- Setsuna-Yuregeshi

O yeah, that's important @jdoe0001

- jdoe0001

got any given choices?

- Setsuna-Yuregeshi

What is the name of this part of the course? Like in the textbook, whats the unit or whatever.

- jdoe0001

that is, what are they expecting as answer, a numeric value? an expression?

- anonymous

i think a value. in degrees or something. The "ABC" has that little angle sign in front of it

- Setsuna-Yuregeshi

But are there any choices?

- anonymous

nope. its called Sides and Angles of Congruent Triangles

- jdoe0001

ok... have you covered SOH CAH TOA yet? that is \(sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad \qquad
% cosine
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\ \quad \\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\)

- anonymous

i have never seen this before in my life

- jdoe0001

because... congruence is not going to get you far on this one, nor similarility

- Setsuna-Yuregeshi

You're in the geometry course right? Or?
If so, I believe SOH CAH TOA is supposed to be covered towards the end of algebra 1.

- anonymous

i never covered it though

- Setsuna-Yuregeshi

After you get the answer to your initial question I can explain SOH CAH TOA. Because if u answer using that when it has not been taught or covered so far, that will be suspicious or something.

- jdoe0001

so.. I'd think this exercise may not apply to you then
since you have not covered that, and I don't see how congruence will help on this triangle

- anonymous

its on a graph though...so do the points count?

- jdoe0001

yes... is on a grid, I can see that much
so each vertex, A, B and C, have some coordinate
to get their segment length, you'd need the distance formula
that's simple enough
but once you get the segment's length, you'd need to apply ..... hmm I'd use the law of cosines, to get any of the angles
and you haven't covered any of that, thus, it may not apply to you

- Setsuna-Yuregeshi

Or what if it has but, it was just forgotten?

- jdoe0001

forgotten? then.... that may be a signal to call the amnesiac MD I'd thik =)

- anonymous

its on an assignment i have to do. and i already calculated the the length.

- jdoe0001

may well be, but you haven't covered the subject yet
so... not much you could do there, without covering the subject the teacher hasn't done
it is not very helpful if one is covering say... chapter 3
and dispenses exercises for students for chapter 6
if you're in say chapter 3, then that's what needs to be assigned

- anonymous

one of the criteria is this though : Measure the angles of ABC and its images.

- jdoe0001

maybe you're asked to use a protractor :), so.. use one hehe, that'd be simple

- Setsuna-Yuregeshi

Is this homework or something? do you just fill in the blank? Or do you have to show your work?

- anonymous

i have a protractor very simple. so how would i measure angle ABC with a protractor

- jdoe0001

is it mineral, vegetable or animal? =)

- anonymous

?? xD

- Setsuna-Yuregeshi

Is that a joke?
I don't get it.

- anonymous

me either lol

- Setsuna-Yuregeshi

Do you just put the answer? Or do you need to show your work?

- jdoe0001

https://www.youtube.com/watch?v=t4xCOUNEInI

- anonymous

just the answer. how would i do it with a protractor if i can use one

- Setsuna-Yuregeshi

@jdoe0001 Is that where the joke is from?

- Setsuna-Yuregeshi

Look at @jdoe0001's video.

- anonymous

i know how to use a protractor. i just need to know which lines make up angle ABC

- jdoe0001

Setsuna-Yuregeshi joke? hehe

- Setsuna-Yuregeshi

It's this angle: |dw:1436228171391:dw|

- Setsuna-Yuregeshi

In the pic you originally posted. It's the one that looks kinda like that.

- jdoe0001

|dw:1436228999016:dw|

- jdoe0001

|dw:1436229100396:dw|

- Setsuna-Yuregeshi

How did you get it to be a different color?

- Setsuna-Yuregeshi

O wait, never mind.

- anonymous

ohh omg thanks. but which of the lines do i measure. the obtuse or the acute?

- jdoe0001

@Setsuna-Yuregeshi click on [Draw] then click on [copy previous drawing]
scroll up, pick it by clicking,
then draw on it
or delete from it by using the [selection] tool and pressing delete key

- Setsuna-Yuregeshi

In the beginning you said you needed to measure ABC and ACB, look at @jdoe0001's drawings. He tells you which drawings are for which angles...

- anonymous

yea. but which line do i measure, and which one do i put in the bottom line of the protractor

- jdoe0001

either will do

- jdoe0001

either line
if you put on one, it'll give the same angle as if you were to put it on the other
same angle

- anonymous

i get it now. thanks so much for your help.

- Setsuna-Yuregeshi

If you want, later we could teach you about SOH CAH TOA

- anonymous

okay mabye

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