find the discontinuinty of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 2?

- anonymous

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- schrodinger

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- anonymous

|dw:1436228508096:dw|

- anonymous

combine like terms

- anonymous

?? Ok I'm confused

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- anonymous

@nerlineg

- anonymous

any ideas?

- anonymous

6x-6 WHY ARE U YELLING?!

- anonymous

BUT WHAT IS THE DISCONTUNITY?

- anonymous

@mathway A little help?

- anonymous

OPPS I READ IT WRONG

- anonymous

LET ME ASK MY LIL SIS

- anonymous

Thank you!

- anonymous

no chooses ?

- anonymous

nope. They're just graphs and I don't know how to send'em

- anonymous

Ok. I will try

- anonymous

yea we need the graph

- anonymous

hold on guys

- anonymous

@muscrat123 yess it is

- anonymous

Ok, ask him to attach the graphs bcuz it won't work for me

- anonymous

can someone graph 4x^2+16/ 2x-4 for me?

- anonymous

Nope. we have 2 different questions

- anonymous

oh hold plese

- anonymous

kk

- anonymous

@campbell_st

- anonymous

he'll help u in a min

- anonymous

kk:)

- anonymous

Can u help me find the disconuinty or graph it?

- campbell_st

ok... so this graph has 2 asymptotes
the vertical asymptote is when
2x + 65 = 0
and there is an oblique asymptote which can be found using polynomial division of synthetic division.

- anonymous

here you goo ! :)

- anonymous

Thanks:)

- anonymous

So what would the graph look like?

- campbell_st

so you need a vertical asymptote... you can find it by solving
2x + 65 = 0
the denominator can't be zero... and the value that makes it zero is the asymptote
can you find it..?

- anonymous

I haven't learned that yet. That's my next lesson. This lesson is on discontinuities :(

- campbell_st

ok... then if you haven't done it you really can't do the question...
have you done polynomial division or synthetic division...?

- anonymous

yes

- campbell_st

but just as an exercise
what value of x makes
2x + 65 = 0

- anonymous

Um..idk? Kinda slow in math

- anonymous

sorry

- campbell_st

well here is the 1st step... subtract 65 from both sides of the equation
2x = -65
now solve for x

- anonymous

-32.5

- campbell_st

great so the curve will look like
|dw:1436229958265:dw|

- anonymous

yes

- campbell_st

so the next part is the oblique asymptote
|dw:1436230021718:dw|
do the division the quotient will be the oblique asymptote that you would need to draw

- anonymous

ok :)

- anonymous

hold on please

- anonymous

2x-69

- anonymous

np

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