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anonymous

  • one year ago

find the discontinuinty of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 2?

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  1. anonymous
    • one year ago
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    |dw:1436228508096:dw|

  2. anonymous
    • one year ago
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    combine like terms

  3. anonymous
    • one year ago
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    ?? Ok I'm confused

  4. anonymous
    • one year ago
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    @nerlineg

  5. anonymous
    • one year ago
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    any ideas?

  6. anonymous
    • one year ago
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    6x-6 WHY ARE U YELLING?!

  7. anonymous
    • one year ago
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    BUT WHAT IS THE DISCONTUNITY?

  8. anonymous
    • one year ago
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    @mathway A little help?

  9. anonymous
    • one year ago
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    OPPS I READ IT WRONG

  10. anonymous
    • one year ago
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    LET ME ASK MY LIL SIS

  11. anonymous
    • one year ago
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    Thank you!

  12. anonymous
    • one year ago
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    no chooses ?

  13. anonymous
    • one year ago
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    nope. They're just graphs and I don't know how to send'em

  14. anonymous
    • one year ago
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    Ok. I will try

  15. anonymous
    • one year ago
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    yea we need the graph

  16. anonymous
    • one year ago
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    hold on guys

  17. anonymous
    • one year ago
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    @muscrat123 yess it is

  18. anonymous
    • one year ago
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    Ok, ask him to attach the graphs bcuz it won't work for me

  19. anonymous
    • one year ago
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    can someone graph 4x^2+16/ 2x-4 for me?

  20. anonymous
    • one year ago
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    Nope. we have 2 different questions

  21. anonymous
    • one year ago
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    oh hold plese

  22. anonymous
    • one year ago
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    kk

  23. anonymous
    • one year ago
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    @campbell_st

  24. anonymous
    • one year ago
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    he'll help u in a min

  25. anonymous
    • one year ago
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    kk:)

  26. anonymous
    • one year ago
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    Can u help me find the disconuinty or graph it?

  27. campbell_st
    • one year ago
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    ok... so this graph has 2 asymptotes the vertical asymptote is when 2x + 65 = 0 and there is an oblique asymptote which can be found using polynomial division of synthetic division.

  28. anonymous
    • one year ago
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    here you goo ! :)

  29. anonymous
    • one year ago
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    Thanks:)

  30. anonymous
    • one year ago
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    So what would the graph look like?

  31. campbell_st
    • one year ago
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    so you need a vertical asymptote... you can find it by solving 2x + 65 = 0 the denominator can't be zero... and the value that makes it zero is the asymptote can you find it..?

  32. anonymous
    • one year ago
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    I haven't learned that yet. That's my next lesson. This lesson is on discontinuities :(

  33. campbell_st
    • one year ago
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    ok... then if you haven't done it you really can't do the question... have you done polynomial division or synthetic division...?

  34. anonymous
    • one year ago
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    yes

  35. campbell_st
    • one year ago
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    but just as an exercise what value of x makes 2x + 65 = 0

  36. anonymous
    • one year ago
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    Um..idk? Kinda slow in math

  37. anonymous
    • one year ago
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    sorry

  38. campbell_st
    • one year ago
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    well here is the 1st step... subtract 65 from both sides of the equation 2x = -65 now solve for x

  39. anonymous
    • one year ago
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    -32.5

  40. campbell_st
    • one year ago
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    great so the curve will look like |dw:1436229958265:dw|

  41. anonymous
    • one year ago
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    yes

  42. campbell_st
    • one year ago
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    so the next part is the oblique asymptote |dw:1436230021718:dw| do the division the quotient will be the oblique asymptote that you would need to draw

  43. anonymous
    • one year ago
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    ok :)

  44. anonymous
    • one year ago
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    hold on please

  45. anonymous
    • one year ago
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    2x-69

  46. anonymous
    • one year ago
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    np

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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