anonymous
  • anonymous
find the discontinuinty of f(x) = the quantity of 4 x squared minus 4 x minus 8, all over 2 x plus 2?
Mathematics
jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1436228508096:dw|
anonymous
  • anonymous
combine like terms
anonymous
  • anonymous
?? Ok I'm confused

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anonymous
  • anonymous
anonymous
  • anonymous
any ideas?
anonymous
  • anonymous
6x-6 WHY ARE U YELLING?!
anonymous
  • anonymous
BUT WHAT IS THE DISCONTUNITY?
anonymous
  • anonymous
@mathway A little help?
anonymous
  • anonymous
OPPS I READ IT WRONG
anonymous
  • anonymous
LET ME ASK MY LIL SIS
anonymous
  • anonymous
Thank you!
anonymous
  • anonymous
no chooses ?
anonymous
  • anonymous
nope. They're just graphs and I don't know how to send'em
anonymous
  • anonymous
Ok. I will try
anonymous
  • anonymous
yea we need the graph
anonymous
  • anonymous
hold on guys
anonymous
  • anonymous
@muscrat123 yess it is
anonymous
  • anonymous
Ok, ask him to attach the graphs bcuz it won't work for me
anonymous
  • anonymous
can someone graph 4x^2+16/ 2x-4 for me?
anonymous
  • anonymous
Nope. we have 2 different questions
anonymous
  • anonymous
oh hold plese
anonymous
  • anonymous
kk
anonymous
  • anonymous
anonymous
  • anonymous
he'll help u in a min
anonymous
  • anonymous
kk:)
anonymous
  • anonymous
Can u help me find the disconuinty or graph it?
campbell_st
  • campbell_st
ok... so this graph has 2 asymptotes the vertical asymptote is when 2x + 65 = 0 and there is an oblique asymptote which can be found using polynomial division of synthetic division.
anonymous
  • anonymous
here you goo ! :)
anonymous
  • anonymous
Thanks:)
anonymous
  • anonymous
So what would the graph look like?
campbell_st
  • campbell_st
so you need a vertical asymptote... you can find it by solving 2x + 65 = 0 the denominator can't be zero... and the value that makes it zero is the asymptote can you find it..?
anonymous
  • anonymous
I haven't learned that yet. That's my next lesson. This lesson is on discontinuities :(
campbell_st
  • campbell_st
ok... then if you haven't done it you really can't do the question... have you done polynomial division or synthetic division...?
anonymous
  • anonymous
yes
campbell_st
  • campbell_st
but just as an exercise what value of x makes 2x + 65 = 0
anonymous
  • anonymous
Um..idk? Kinda slow in math
anonymous
  • anonymous
sorry
campbell_st
  • campbell_st
well here is the 1st step... subtract 65 from both sides of the equation 2x = -65 now solve for x
anonymous
  • anonymous
-32.5
campbell_st
  • campbell_st
great so the curve will look like |dw:1436229958265:dw|
anonymous
  • anonymous
yes
campbell_st
  • campbell_st
so the next part is the oblique asymptote |dw:1436230021718:dw| do the division the quotient will be the oblique asymptote that you would need to draw
anonymous
  • anonymous
ok :)
anonymous
  • anonymous
hold on please
anonymous
  • anonymous
2x-69
anonymous
  • anonymous
np

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