anonymous
  • anonymous
Lim sqrt (2c-a) -a/a-c x -> ∞
Calculus1
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\lim x ->\infty \left(\begin{matrix}\sqrt{(2c-a)} -a\\ a-c\end{matrix}\right)\]
dan815
  • dan815
|dw:1436230985174:dw|
dan815
  • dan815
|dw:1436231037370:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

dan815
  • dan815
lim c--> inf? a--> inf?
anonymous
  • anonymous
Why are you putting factorials in
anonymous
  • anonymous
I'll assume the x should be c or a, doesn't matter Do you know to multiply top and bottom by (sqrt 2c-a) +a
dan815
  • dan815
misunderstood question
anonymous
  • anonymous
and once you do you have (2c-a)-a on top (a-c)(sqrt (2c-a) + a on bottom now factor out -2 on top and you have -2(a-c) -a and you can cancel out the (a-c)
anonymous
  • anonymous
and now you are at the point where it matters if your x is supposed to be a or c
anonymous
  • anonymous
My x is c
anonymous
  • anonymous
ok its 0 then
anonymous
  • anonymous
did you follow the above steps or would it be easier in equation form
dan815
  • dan815
|dw:1436231821569:dw|
anonymous
  • anonymous
Yes i follow the steps
anonymous
  • anonymous
dan815 but if you repalce x for a you got a indetermination
dan815
  • dan815
can you clarify your question lim ?-->inf
anonymous
  • anonymous
Is lim when c --> a sorry I misspelled the question
dan815
  • dan815
oh in that case, you have to follow kheaths steps
dan815
  • dan815
|dw:1436232533144:dw|
dan815
  • dan815
looks like he did not give you the right steps exactly, so work it out from here
dan815
  • dan815
@ganeshie8
dan815
  • dan815
|dw:1436233090915:dw|
ganeshie8
  • ganeshie8
looks the original question has so many typoes @Gloria63 please take a screenshot and attach if psble
anonymous
  • anonymous
\[\lim c ->a, \frac{ \sqrt{(2c-a)} -a}{a -c }\]
anonymous
  • anonymous
1 Attachment
anonymous
  • anonymous
@ganeshie8 this is the original source
ganeshie8
  • ganeshie8
not so sure wolf says the two sided limit doesn't exist http://www.wolframalpha.com/input/?i=lim%28c%5Cto+a%29+%28sqrt%282c-a%29-a%29%2F%28a-c%29
ganeshie8
  • ganeshie8
@dan815
anonymous
  • anonymous
Tyvm to all for your help.

Looking for something else?

Not the answer you are looking for? Search for more explanations.