A candy bar box is in the shape of a triangular prism. The volume of the box is 1,200 cubic centimeters.
Part A: What is the height of the box? Show your work. (5 points)
Part B: What is the approximate amount of cardboard used to make the sides of the candy box? Explain how you got your answer. (5 points)

- muscrat123

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- ganeshie8

picture?

- muscrat123

##### 1 Attachment

- muscrat123

@ganeshie8

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## More answers

- ganeshie8

that picture doesn't look right,
height is already there in the picture

- muscrat123

i copied it directly from the page. which number is the height? i thought the same but wanted to make sure

- ganeshie8

height = distance between triangular bases

- muscrat123

but which number is it? there are 2 numbers next to the height

- muscrat123

nm. its 13 right?

- ganeshie8

|dw:1436232499596:dw|

- ganeshie8

distance between the triangular bases is 20cm right

- muscrat123

is that the height of the box?

- muscrat123

i thought that was the length

- ganeshie8

Yes thats the height of the box

- jim_thompson5910

|dw:1436232791136:dw|

- jim_thompson5910

I think they want they want the length of this segment here
|dw:1436232861596:dw|

- ganeshie8

thats the height of base, not box

- jim_thompson5910

if so, then focus on this triangle
|dw:1436232912171:dw|
imagine looking directly at this triangle
|dw:1436232983737:dw|

- jim_thompson5910

|dw:1436233051396:dw|

- muscrat123

is it 12?

- jim_thompson5910

yeah because we have a 5-12-13 right triangle
|dw:1436233124402:dw|

- jim_thompson5910

that is of course, assuming that's what they meant by "height"

- muscrat123

so it Is 12?

- jim_thompson5910

yeah

- muscrat123

thx. but i dont understand part b

- jim_thompson5910

you have 3 lateral sides
Right face
|dw:1436233275185:dw|

- jim_thompson5910

left face (hidden)
|dw:1436233294238:dw|

- jim_thompson5910

and the bottom face (also hidden)
|dw:1436233324795:dw|

- jim_thompson5910

they are the lateral faces

- jim_thompson5910

find the area of each lateral face, then add up the areas

- muscrat123

how would i find the area of the lateral faces?

- jim_thompson5910

each is a rectangle

- jim_thompson5910

for instance, the bottom face is a 10 by 20 rectangle

- muscrat123

thats 200

- jim_thompson5910

|dw:1436233428096:dw|

- jim_thompson5910

do the same for the other rectangles

- jim_thompson5910

also, don't forget about the triangles as well

- muscrat123

how did we get 12 again?

- muscrat123

for part a

- jim_thompson5910

did you randomly guess 12?

- jim_thompson5910

you were the first one to write it

- muscrat123

no. i did some random equations and it sounded right to me

- jim_thompson5910

|dw:1436233600130:dw|

- jim_thompson5910

That's the pythagorean theorem

- muscrat123

ok. thx.

- jim_thompson5910

np

- muscrat123

for part b it says approximate though. do we have to round?

- muscrat123

if we dont round, i got 850 for part b

- jim_thompson5910

not always
approximate just means that it's some decimal that usually goes on forever
example: 1/7 = 0.14285714285714
the "142857" repeats forever over and over. So one approximation of 1/7 is 0.14286. Another approximation is 0.1429

- jim_thompson5910

so yeah I guess in a way, you are rounding

- muscrat123

is 850 correct?

- jim_thompson5910

close but no

- muscrat123

what is it?

- jim_thompson5910

how did you get 850? can you show your work?

- muscrat123

yes. hold on a sec

- muscrat123

|dw:1436234036932:dw|

- muscrat123

@jim_thompson5910

- jim_thompson5910

the triangle portion is where you made an error

- jim_thompson5910

each triangle has a base of 10 and height of 12

- muscrat123

oh right!!! i forgot about that part. hold on so i can fix it.

- muscrat123

840 is the correct answer

- jim_thompson5910

yep, 840 square cm

- muscrat123

thx!!!

- jim_thompson5910

sure thing

- muscrat123

is it squared or cubed?

- jim_thompson5910

surface area deals with square units (not cubic units)

- muscrat123

ok thx

- jim_thompson5910

yw

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