muscrat123
  • muscrat123
A candy bar box is in the shape of a triangular prism. The volume of the box is 1,200 cubic centimeters. Part A: What is the height of the box? Show your work. (5 points) Part B: What is the approximate amount of cardboard used to make the sides of the candy box? Explain how you got your answer. (5 points)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
ganeshie8
  • ganeshie8
picture?
muscrat123
  • muscrat123
muscrat123
  • muscrat123
@ganeshie8

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

ganeshie8
  • ganeshie8
that picture doesn't look right, height is already there in the picture
muscrat123
  • muscrat123
i copied it directly from the page. which number is the height? i thought the same but wanted to make sure
ganeshie8
  • ganeshie8
height = distance between triangular bases
muscrat123
  • muscrat123
but which number is it? there are 2 numbers next to the height
muscrat123
  • muscrat123
nm. its 13 right?
ganeshie8
  • ganeshie8
|dw:1436232499596:dw|
ganeshie8
  • ganeshie8
distance between the triangular bases is 20cm right
muscrat123
  • muscrat123
is that the height of the box?
muscrat123
  • muscrat123
i thought that was the length
ganeshie8
  • ganeshie8
Yes thats the height of the box
jim_thompson5910
  • jim_thompson5910
|dw:1436232791136:dw|
jim_thompson5910
  • jim_thompson5910
I think they want they want the length of this segment here |dw:1436232861596:dw|
ganeshie8
  • ganeshie8
thats the height of base, not box
jim_thompson5910
  • jim_thompson5910
if so, then focus on this triangle |dw:1436232912171:dw| imagine looking directly at this triangle |dw:1436232983737:dw|
jim_thompson5910
  • jim_thompson5910
|dw:1436233051396:dw|
muscrat123
  • muscrat123
is it 12?
jim_thompson5910
  • jim_thompson5910
yeah because we have a 5-12-13 right triangle |dw:1436233124402:dw|
jim_thompson5910
  • jim_thompson5910
that is of course, assuming that's what they meant by "height"
muscrat123
  • muscrat123
so it Is 12?
jim_thompson5910
  • jim_thompson5910
yeah
muscrat123
  • muscrat123
thx. but i dont understand part b
jim_thompson5910
  • jim_thompson5910
you have 3 lateral sides Right face |dw:1436233275185:dw|
jim_thompson5910
  • jim_thompson5910
left face (hidden) |dw:1436233294238:dw|
jim_thompson5910
  • jim_thompson5910
and the bottom face (also hidden) |dw:1436233324795:dw|
jim_thompson5910
  • jim_thompson5910
they are the lateral faces
jim_thompson5910
  • jim_thompson5910
find the area of each lateral face, then add up the areas
muscrat123
  • muscrat123
how would i find the area of the lateral faces?
jim_thompson5910
  • jim_thompson5910
each is a rectangle
jim_thompson5910
  • jim_thompson5910
for instance, the bottom face is a 10 by 20 rectangle
muscrat123
  • muscrat123
thats 200
jim_thompson5910
  • jim_thompson5910
|dw:1436233428096:dw|
jim_thompson5910
  • jim_thompson5910
do the same for the other rectangles
jim_thompson5910
  • jim_thompson5910
also, don't forget about the triangles as well
muscrat123
  • muscrat123
how did we get 12 again?
muscrat123
  • muscrat123
for part a
jim_thompson5910
  • jim_thompson5910
did you randomly guess 12?
jim_thompson5910
  • jim_thompson5910
you were the first one to write it
muscrat123
  • muscrat123
no. i did some random equations and it sounded right to me
jim_thompson5910
  • jim_thompson5910
|dw:1436233600130:dw|
jim_thompson5910
  • jim_thompson5910
That's the pythagorean theorem
muscrat123
  • muscrat123
ok. thx.
jim_thompson5910
  • jim_thompson5910
np
muscrat123
  • muscrat123
for part b it says approximate though. do we have to round?
muscrat123
  • muscrat123
if we dont round, i got 850 for part b
jim_thompson5910
  • jim_thompson5910
not always approximate just means that it's some decimal that usually goes on forever example: 1/7 = 0.14285714285714 the "142857" repeats forever over and over. So one approximation of 1/7 is 0.14286. Another approximation is 0.1429
jim_thompson5910
  • jim_thompson5910
so yeah I guess in a way, you are rounding
muscrat123
  • muscrat123
is 850 correct?
jim_thompson5910
  • jim_thompson5910
close but no
muscrat123
  • muscrat123
what is it?
jim_thompson5910
  • jim_thompson5910
how did you get 850? can you show your work?
muscrat123
  • muscrat123
yes. hold on a sec
muscrat123
  • muscrat123
|dw:1436234036932:dw|
muscrat123
  • muscrat123
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
the triangle portion is where you made an error
jim_thompson5910
  • jim_thompson5910
each triangle has a base of 10 and height of 12
muscrat123
  • muscrat123
oh right!!! i forgot about that part. hold on so i can fix it.
muscrat123
  • muscrat123
840 is the correct answer
jim_thompson5910
  • jim_thompson5910
yep, 840 square cm
muscrat123
  • muscrat123
thx!!!
jim_thompson5910
  • jim_thompson5910
sure thing
muscrat123
  • muscrat123
is it squared or cubed?
jim_thompson5910
  • jim_thompson5910
surface area deals with square units (not cubic units)
muscrat123
  • muscrat123
ok thx
jim_thompson5910
  • jim_thompson5910
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.