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- anonymous

Suppose that you have 10 cards. 6 are green and 4 are yellow. The 6 green cards are numbered 1, 2, 3, 4, 5, and 6. The 4 yellow cards are numbered 1, 2, 3, and 4. The cards are well shuffled. You randomly draw one card.
• G = card drawn is green
• Y = card drawn is yellow
• E = card drawn is even-numbered
How do we find:
P(G | E)
P(G or E)

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- anonymous

- katieb

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- dan815

P(G | E) means prob of GREEN given that the card is EVEN

- dan815

there are a total of 5 even cards, of which 3 are green

- anonymous

ohhh so it would be 3/5?

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- dan815

yes

- anonymous

oh okay I got it
and how about approaching an "OR"

- anonymous

would it be 8/10?

- dan815

yes

- Loser66

dan?

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