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anonymous

  • one year ago

Suppose that you have 10 cards. 6 are green and 4 are yellow. The 6 green cards are numbered 1, 2, 3, 4, 5, and 6. The 4 yellow cards are numbered 1, 2, 3, and 4. The cards are well shuffled. You randomly draw one card. • G = card drawn is green • Y = card drawn is yellow • E = card drawn is even-numbered How do we find: P(G | E) P(G or E)

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  1. dan815
    • one year ago
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    P(G | E) means prob of GREEN given that the card is EVEN

  2. dan815
    • one year ago
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    there are a total of 5 even cards, of which 3 are green

  3. anonymous
    • one year ago
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    ohhh so it would be 3/5?

  4. dan815
    • one year ago
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    yes

  5. anonymous
    • one year ago
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    oh okay I got it and how about approaching an "OR"

  6. anonymous
    • one year ago
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    would it be 8/10?

  7. dan815
    • one year ago
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    yes

  8. Loser66
    • one year ago
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    dan?

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