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anonymous

  • one year ago

http://media.education2020.com/evresources/2072227_circle_in_circle.png Find the circumference of the larger circle if the area of one of the smaller circles is 48 pi in2. Will give medal and fan and testimony

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  1. jim_thompson5910
    • one year ago
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    " the area of one of the smaller circles is 48 pi in2" use this info to find the radius of the smaller circle

  2. jim_thompson5910
    • one year ago
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    Area of a circle \[\Large A = \pi*r^2\]

  3. anonymous
    • one year ago
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    Would 48 be the diameter?

  4. jim_thompson5910
    • one year ago
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    no, 48pi is the area

  5. jim_thompson5910
    • one year ago
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    A = 48pi

  6. wolf1728
    • one year ago
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    48 = PI * r^2 r^2 = 48 / PI

  7. anonymous
    • one year ago
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    So would i do 48*pi? Im so confused on this :(

  8. jim_thompson5910
    • one year ago
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    \[\Large A = \pi*r^2\] \[\Large 48\pi = \pi*r^2\] \[\Large 48 = r^2\] the pi's cancel. Solve for r

  9. anonymous
    • one year ago
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    So this\[\sqrt{48}=r ^{2}\]

  10. jim_thompson5910
    • one year ago
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    more like \[\Large r = \sqrt{48}\]

  11. jim_thompson5910
    • one year ago
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    you can simplify that radical

  12. anonymous
    • one year ago
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    I got 6.92 for the answer

  13. wolf1728
    • one year ago
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    Here's a quick answer: It appears that the smaller circle has a radius that is .5 the radius of the larger circle. When calculating area, when you double the size the area increases FOUR times. SO, area of larger circle = 4 * 48 = 192

  14. jim_thompson5910
    • one year ago
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    it wants the circumference of the larger circle

  15. anonymous
    • one year ago
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    Im really sorry that confused me even more :( like all my answer choices are in radical form

  16. wolf1728
    • one year ago
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    What are your answer choices?

  17. jim_thompson5910
    • one year ago
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    |dw:1436235139053:dw|

  18. jim_thompson5910
    • one year ago
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    |dw:1436235225907:dw|

  19. anonymous
    • one year ago
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    http://media.education2020.com/evresources/2072227_4cb2fce2-9f6e-455d-a731-39e53bec85cd.png

  20. jim_thompson5910
    • one year ago
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    |dw:1436235275013:dw|

  21. jim_thompson5910
    • one year ago
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    Now use the circumference of a circle formula \[\Large C = 2*\pi*r\] You'll plug in r = 2*sqrt(48)

  22. anonymous
    • one year ago
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    Ugh...this is not helping me not be confused. Really sorry for taking up so much tome

  23. anonymous
    • one year ago
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    *time

  24. anonymous
    • one year ago
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  25. jim_thompson5910
    • one year ago
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    @ANA789 do you see how I got the values in my drawing?

  26. anonymous
    • one year ago
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    @jim_thompson5910 Yeah I got that but the answer i got was the same and it was wrong

  27. jim_thompson5910
    • one year ago
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    when you plug r = 2*sqrt(48) into that circumference formula, what do you get?

  28. anonymous
    • one year ago
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    13.85

  29. jim_thompson5910
    • one year ago
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    leave it in radical form though

  30. anonymous
    • one year ago
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    I dont know how to put that in radical form

  31. jim_thompson5910
    • one year ago
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    |dw:1436235731159:dw|

  32. jim_thompson5910
    • one year ago
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    |dw:1436235759458:dw|

  33. jim_thompson5910
    • one year ago
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    |dw:1436235791532:dw|

  34. jim_thompson5910
    • one year ago
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    |dw:1436235814441:dw|

  35. jim_thompson5910
    • one year ago
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    the only thing left to do here is to simplify the root

  36. anonymous
    • one year ago
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    Yeah I got 87.06 for that

  37. jim_thompson5910
    • one year ago
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    simplify \(\Large \sqrt{48}\) to get ??

  38. jim_thompson5910
    • one year ago
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    hint: 48 = 16*3

  39. anonymous
    • one year ago
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    OH!! I SEE NOW!! OKay then thank you :) I know the answer now haha i feel dumb!

  40. jim_thompson5910
    • one year ago
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    its ok, your answer would work if they wanted the approximate result

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