## lisa123 one year ago simplify (|pi-2^3|)/(8-pi)- 3+14÷2-5

1. lisa123

its a pemdas type of problem

2. lisa123

the answer is -4 I just don't know how to get it

3. DecentNabeel

first slove the parenthesis then apply DMAS rule

4. DecentNabeel

ok

5. DecentNabeel

$\frac{14}{2}-3-5+\frac{\left|\pi -2^3\right|}{-\pi +8}$ $\mathrm{Divide\:the\:numbers:}\:\frac{14}{2}=7$ $=\frac{\left|\pi -2^3\right|}{-\pi +8}-3-5+7$ $\mathrm{Add/Subtract\:the\:numbers:}\:-3-5+7=-1$ $=\frac{\left|\pi -2^3\right|}{-\pi +8}-$ $\mathrm{Combine\:the\:fractions\:using\:the\:LCD}:\quad \frac{\left|\pi -2^3\right|}{-\pi +8}-1=\frac{-\left(-\pi +8\right)+\left|\pi -2^3\right|}{-\pi +8}$ $=\frac{-\left(-\pi +8\right)+\left|\pi -2^3\right|}{-\pi +8}$ $=\frac{-\left(-\pi +8\right)+\left|\pi -8\right|}{-\pi +8}$ $\mathrm{Expand}\:-\left(-\pi +8\right):\quad \pi -8$ $=\frac{\left|\pi -8\right|-8+\pi }{-\pi +8}$ $\frac{14}{2}-3-5+\frac{\left|\pi -2^3\right|}{-\pi +8}=\frac{\left|\pi -8\right|-8+\pi }{-\pi +8}\quad \left(\mathrm{Decimal:\quad }\:0\right)$

6. DecentNabeel

ok @lisa123

7. lisa123

ok but why is the answer not -4?

8. DecentNabeel

the answer is 0 not -4

9. DecentNabeel

or you sure the answer is -4 @lisa123

10. lisa123

that's what I got on mathway

11. lisa123

oh Im soooo sorry guys! theres a bracket in -(3+14 div 2 -5). I have to distribute the negative right?

12. DecentNabeel

$-\left(\frac{14}{2}+3-5\right)+\frac{\left|\pi -2^3\right|}{-\pi +8}=\frac{-5\left(-\pi +8\right)+\left|\pi -8\right|}{-\pi +8}\quad \left(\mathrm{Decimal:\quad }\:-4\right)$

13. lisa123

oh ok! thank you @DecentNabeel and @LynFran

14. DecentNabeel

$\mathrm{Simplify}\:-\left(\frac{14}{2}+3-5\right):\quad -5$ $=\frac{\left|\pi -2^3\right|}{-\pi +8}-5$ $\mathrm{Combine\:the\:fractions\:using\:the\:LCD}:\quad \frac{\left|\pi -2^3\right|}{-\pi +8}-5=\frac{-5\left(-\pi +8\right)+\left|\pi -2^3\right|}{-\pi +8}$ $=\frac{-5\left(-\pi +8\right)+\left|\pi -2^3\right|}{-\pi +8}$ $\frac{-5\left(-\pi +8\right)+\left|\pi -8\right|}{-\pi +8}\quad \left(\mathrm{Decimal:\quad }\:-4\right)$

15. DecentNabeel

are you understand @lisa123