## YumYum247 one year ago h

1. YumYum247

|dw:1436204863057:dw|

2. YumYum247

Since.... 1 Node = 1 Loop = λ/2 2 Node = 2 Loops = λ If one Node = 0.40m two Nodes = 0.80m Therefore the 2 Nodes = Wavelength = 0.80m, the wavelength is 0.80m To Figure out the wavelength, we're going to use..........V = f X λ Rearrange the formula so that we're solving for "λ" λ = V/f λ = 6m/sec /0.80m λ = 7.5 or 8Hz Therefore the Frequency is 8Hz

3. YumYum247

@Astrophysics could you please check my work Love?!?!?!?!? :")

4. YumYum247

5. YumYum247

6. YumYum247

the important question here i wanna ask you is that, does the length of 2 Nods equals the wavelength?!?!?!?!?

7. dan815

Frequency is number of cycles per second or in other words the number of wavelengths per second if the the wavelength is 0.8m and the wave is moving at 6m/s how many wave lengths did it move in 1 second? that is 6/0.8 so the frequency is 6/0.8 cyclces/sec or 6/0.8 hz= 6/8/10 = 60/8 = 15/2 Hz

8. YumYum247

dear 0.8m is not the wavelength, that's just my calculations....The question says the difference between two Nodes is 0.40m. Since 2 Loops = 1wavelength, that should also mean that 2 nodes equal 2 loops = wavelength....am i right?!?!?!?

9. YumYum247

therefore the distance between two nodes equals to 1 wavelength.

10. YumYum247

am i right?!?!?!?

11. dan815

12. dan815

hmmph :@

13. YumYum247

cuz i remember wavelength could be any distance between two success crests or trough or the the distance between them on the equilibrim....

14. YumYum247

I asked for his help but he was busy and then left!!!! :"(

15. YumYum247

he's back!!! Yay :"D

16. YumYum247

17. dan815

lol im jk, 0.8 is probably right

18. dan815

|dw:1436241352910:dw|

19. YumYum247

Ummmmm^^^^............................................................o_OO_o

20. YumYum247

this is a little off topic......but you got mad skill dan!!! :"D

21. dan815

HAHAhahaha hahhaahha <33

22. dan815

did u hear that astro

23. YumYum247

sorry people my internet is being internet here -_-

24. Astrophysics

$v = \lambda f \implies f = \frac{ v }{ \lambda } = \frac{ 6 m/s }{ 0.8m } = 7.5Hz$

25. YumYum247

that's what i got!!!

26. Astrophysics

That looks good

27. Astrophysics

What you think danni boi

28. YumYum247

but do you agree with what i said earlier?!?!?!

29. YumYum247

The question says the difference between two Nodes is 0.40m. Since 2 Loops = 1wavelength, that should also mean that 2 nodes equal 2 loops = wavelength....am i right?!?!?!?

30. dan815

i can show u a proof for it

31. Astrophysics

Yeah, good :)

32. YumYum247

ok so the distance between two nodes (0.40m + 0.40m) equals to 1 wavelength = 0.8m

33. Astrophysics

|dw:1436242135453:dw|

34. YumYum247

yes does that equal to the distance of 1 wavelength?!?!?!?!

35. YumYum247

since1 Node = 1 Loop = λ/2 2 Node = 2 Loops = λ If one Node = 0.40m two Nodes = 0.80m Therefore the 2 Nodes = Wavelength = 0.80m, the wavelength is 0.80m

36. Astrophysics

Yes, 2 nodes will make a wavelength we can see this in your calculation as well notice 1 node gives $1~ node = \frac{ \lambda }{ 2 }$ so 2 will give lambda :)

37. Astrophysics

So 1 node is half a wavelength

38. Astrophysics

Don't doubt yourself! You're thinking right, but you need to also compare the concepts to the math and see if it makes sense, :)

39. YumYum247

Thank you soooooooooooooooooooooooooooooooooooooo much!!1 Love you so much!!! Stay blessed and cute as always!!!

40. Astrophysics

Hehe, np ^.^

41. YumYum247

^_^