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- YumYum247

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- schrodinger

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- YumYum247

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- YumYum247

Since....
1 Node = 1 Loop = λ/2
2 Node = 2 Loops = λ
If one Node = 0.40m
two Nodes = 0.80m
Therefore the 2 Nodes = Wavelength = 0.80m, the wavelength is 0.80m
To Figure out the wavelength, we're going to use..........V = f X λ
Rearrange the formula so that we're solving for "λ"
λ = V/f
λ = 6m/sec /0.80m
λ = 7.5 or 8Hz
Therefore the Frequency is 8Hz

- YumYum247

@Astrophysics could you please check my work Love?!?!?!?!? :")

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## More answers

- YumYum247

@dan815 dear can you please help me????????????????

- YumYum247

please check my work :)

- YumYum247

the important question here i wanna ask you is that, does the length of 2 Nods equals the wavelength?!?!?!?!?

- dan815

Frequency is number of cycles per second or in other words the number of wavelengths per second
if the the wavelength is 0.8m
and the wave is moving at 6m/s
how many wave lengths did it move in 1 second?
that is 6/0.8
so the frequency is 6/0.8 cyclces/sec or 6/0.8 hz= 6/8/10 = 60/8 = 15/2 Hz

- YumYum247

dear 0.8m is not the wavelength, that's just my calculations....The question says the difference between two Nodes is 0.40m. Since 2 Loops = 1wavelength, that should also mean that 2 nodes equal 2 loops = wavelength....am i right?!?!?!?

- YumYum247

therefore the distance between two nodes equals to 1 wavelength.

- YumYum247

am i right?!?!?!?

- dan815

why dont you ask ASTROphysics your first choice

- dan815

hmmph :@

- YumYum247

cuz i remember wavelength could be any distance between two success crests or trough or the the distance between them on the equilibrim....

- YumYum247

I asked for his help but he was busy and then left!!!! :"(

- YumYum247

he's back!!! Yay :"D

- YumYum247

@Astrophysics Please help!!!

- dan815

lol im jk, 0.8 is probably right

- dan815

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- YumYum247

Ummmmm^^^^............................................................o_OO_o

- YumYum247

this is a little off topic......but you got mad skill dan!!! :"D

- dan815

HAHAhahaha hahhaahha <33

- dan815

did u hear that astro

- YumYum247

sorry people my internet is being internet here -_-

- Astrophysics

\[v = \lambda f \implies f = \frac{ v }{ \lambda } = \frac{ 6 m/s }{ 0.8m } = 7.5Hz\]

- YumYum247

that's what i got!!!

- Astrophysics

That looks good

- Astrophysics

What you think danni boi

- YumYum247

but do you agree with what i said earlier?!?!?!

- YumYum247

The question says the difference between two Nodes is 0.40m. Since 2 Loops = 1wavelength, that should also mean that 2 nodes equal 2 loops = wavelength....am i right?!?!?!?

- dan815

i can show u a proof for it

- Astrophysics

Yeah, good :)

- YumYum247

ok so the distance between two nodes (0.40m + 0.40m) equals to 1 wavelength = 0.8m

- Astrophysics

|dw:1436242135453:dw|

- YumYum247

yes does that equal to the distance of 1 wavelength?!?!?!?!

- YumYum247

since1
Node = 1 Loop = λ/2
2 Node = 2 Loops = λ
If one Node = 0.40m
two Nodes = 0.80m
Therefore the 2 Nodes = Wavelength = 0.80m, the wavelength is 0.80m

- Astrophysics

Yes, 2 nodes will make a wavelength we can see this in your calculation as well notice 1 node gives \[1~ node = \frac{ \lambda }{ 2 }\] so 2 will give lambda :)

- Astrophysics

So 1 node is half a wavelength

- Astrophysics

Don't doubt yourself! You're thinking right, but you need to also compare the concepts to the math and see if it makes sense, :)

- YumYum247

Thank you soooooooooooooooooooooooooooooooooooooo much!!1 Love you so much!!! Stay blessed and cute as always!!!

- Astrophysics

Hehe, np ^.^

- YumYum247

^_^

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