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anonymous
 one year ago
A pair of equations is shown below.
x + y = 2
y = one halfx + 5
If the two equations are graphed, at what point do the lines representing the two equations intersect?
(4, −2)
(−2, 4)
(2, 5)
(5, −2) Please help I will fail if I dont do this plese help me
anonymous
 one year ago
A pair of equations is shown below. x + y = 2 y = one halfx + 5 If the two equations are graphed, at what point do the lines representing the two equations intersect? (4, −2) (−2, 4) (2, 5) (5, −2) Please help I will fail if I dont do this plese help me

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butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1firstly, you want to make y the subject in the first equation " x + y = 2" :)

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1so can you tell me what it would be?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I know you isolate it but I do not really understand

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1\[x + y = 2 \rightarrow y = x + 2 \] right? All i did was subtract "x" from both sides to make y the subject :)

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1so now we have two equations:dw:1436241915931:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but which answer is it (4, −2) (−2, 4) (2, 5) (5, −2) is what confuses me

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1you know what... here's an easier method. Just plug in the values for each option and see which one satisfies the equation. So for example.. the first option (4, 2), this means x = 4, y = 2 Plug this into the first equation " x + y = 2" 4 + (2) = 2 42 = 2 2=2 So this works :) BUT you have to plug the points into the second equation " y = 1/2x + 5" 4 = 1/2 (2) + 5 4 = 1 + 5 4 = 4 This works SOOO, since (4, 2) works.. this is your point of intersection

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oooooooooooooooohhhhhhhhhhhhhhh that is easy

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.1also, you got lucky that was the first option and it was the answer.When in doubt, plug it in. Don't just demand answers.lol
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