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anonymous

  • one year ago

find the other five trig ratios of angle. sec(angle)= 7/2

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  1. anonymous
    • one year ago
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    for sin of angle i got sqrt 53/7 cos= 2/7 tan=sqrt53/2 csc= 7/sqrt 53 sec=7/2 cot= 2/sqrt 53

  2. sweetburger
    • one year ago
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    |dw:1436242029164:dw|

  3. UsukiDoll
    • one year ago
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    once we find the cosine we can use Pythagorean theorem .

  4. sweetburger
    • one year ago
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    no i mean sqrt(45)

  5. anonymous
    • one year ago
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    i know i have the sin, csc and cot wrong but idk why

  6. UsukiDoll
    • one year ago
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    \[a^2+2^2=7^2 \]

  7. UsukiDoll
    • one year ago
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    we know that sec = 7/2 and that's 1/cosine so for cosine that fraction for sec is in reverse which is 2/7 now since we know 2 sides, we can use the Pythagorean theorem to figure out a (which is our missing side)

  8. anonymous
    • one year ago
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    is it sqrt 45

  9. UsukiDoll
    • one year ago
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    you can simplify that further.

  10. UsukiDoll
    • one year ago
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    like which perfect square number can we get out of 45? _____ x 5 = 45?

  11. anonymous
    • one year ago
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    9

  12. anonymous
    • one year ago
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    so itll b e3 sqrt 5

  13. UsukiDoll
    • one year ago
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    |dw:1436242284373:dw|

  14. anonymous
    • one year ago
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    thank you!

  15. UsukiDoll
    • one year ago
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    |dw:1436242312691:dw| now with this triangle you can find the sine, tangent, cotangent, and csc

  16. UsukiDoll
    • one year ago
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    tangent = opposite/adjacent

  17. UsukiDoll
    • one year ago
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    sine = opposite/hypotenuse

  18. anonymous
    • one year ago
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    sin= 3swrt5/7 csc=7/3srt5

  19. UsukiDoll
    • one year ago
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    and then cotangent is tangent in reverse and csc is sine in reverse

  20. anonymous
    • one year ago
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    cot= 2/3sqrt 5

  21. anonymous
    • one year ago
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    yes i got it thank you :)

  22. UsukiDoll
    • one year ago
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    woo :D

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