anonymous
  • anonymous
find the other five trig ratios of angle. sec(angle)= 7/2
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
for sin of angle i got sqrt 53/7 cos= 2/7 tan=sqrt53/2 csc= 7/sqrt 53 sec=7/2 cot= 2/sqrt 53
sweetburger
  • sweetburger
|dw:1436242029164:dw|
UsukiDoll
  • UsukiDoll
once we find the cosine we can use Pythagorean theorem .

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sweetburger
  • sweetburger
no i mean sqrt(45)
anonymous
  • anonymous
i know i have the sin, csc and cot wrong but idk why
UsukiDoll
  • UsukiDoll
\[a^2+2^2=7^2 \]
UsukiDoll
  • UsukiDoll
we know that sec = 7/2 and that's 1/cosine so for cosine that fraction for sec is in reverse which is 2/7 now since we know 2 sides, we can use the Pythagorean theorem to figure out a (which is our missing side)
anonymous
  • anonymous
is it sqrt 45
UsukiDoll
  • UsukiDoll
you can simplify that further.
UsukiDoll
  • UsukiDoll
like which perfect square number can we get out of 45? _____ x 5 = 45?
anonymous
  • anonymous
9
anonymous
  • anonymous
so itll b e3 sqrt 5
UsukiDoll
  • UsukiDoll
|dw:1436242284373:dw|
anonymous
  • anonymous
thank you!
UsukiDoll
  • UsukiDoll
|dw:1436242312691:dw| now with this triangle you can find the sine, tangent, cotangent, and csc
UsukiDoll
  • UsukiDoll
tangent = opposite/adjacent
UsukiDoll
  • UsukiDoll
sine = opposite/hypotenuse
anonymous
  • anonymous
sin= 3swrt5/7 csc=7/3srt5
UsukiDoll
  • UsukiDoll
and then cotangent is tangent in reverse and csc is sine in reverse
anonymous
  • anonymous
cot= 2/3sqrt 5
anonymous
  • anonymous
yes i got it thank you :)
UsukiDoll
  • UsukiDoll
woo :D

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