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anonymous

  • one year ago

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  1. anonymous
    • one year ago
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    |dw:1436242811607:dw|

  2. Astrophysics
    • one year ago
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    use your trig triangles|dw:1436242932162:dw|

  3. Astrophysics
    • one year ago
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    Now use your trig ratios to figure it out, with the triangles

  4. Astrophysics
    • one year ago
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    |dw:1436243008504:dw|

  5. anonymous
    • one year ago
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    could i use the unit circle and put it this way? (1/2) (1/2) + (sqrt3/2) (sqrt 3/2)

  6. Astrophysics
    • one year ago
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    You could use unit circle!

  7. Astrophysics
    • one year ago
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    This is part of the unit circle, but if you're more comfortable with the circle itself, that's great :)

  8. Astrophysics
    • one year ago
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    That looks good, now simplify it

  9. anonymous
    • one year ago
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    okay so i got 1/4+3/2?

  10. Astrophysics
    • one year ago
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    What is \[\frac{ \sqrt{3} }{ 2 } \times \frac{ \sqrt{3} }{ 2 }\]

  11. anonymous
    • one year ago
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    sqrt 9/4

  12. anonymous
    • one year ago
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    i got it! thank you the answer would be 1

  13. Astrophysics
    • one year ago
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    Yup :)

  14. anonymous
    • one year ago
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    ok on to the next one lol

  15. UsukiDoll
    • one year ago
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    a square root x a square root is just the number itself \[\sqrt{3} \times \sqrt{3} = 3 \] in exponential form \[3^{\frac{1}{2}}3^{\frac{1}{2}} \rightarrow 3^{\frac{1}{2}+\frac{1}{2}} \rightarrow 3^{\frac{2}{2}} \rightarrow 3^1 \rightarrow 3\]

  16. UsukiDoll
    • one year ago
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    you would be asked to simplified further so we had to take that extra step... otherwise everything is correct, but careful there are teachers/professors who have no problem taking points off for not giving a simplified answer.

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