A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
5. A ball of mass m is suspended above the center of the rotating platform on the elastic
spring with stiffness k and initial (nonstretched) length lo as shown. The opposite end of
the spring is attached to the vertical pole fixed on axis of the platform. The platform starts
to rotate with angular velocity w. What is the angle a' that the spring makes with the
vertical? Consider all values of the angular velocity, from w=0 to w=inf and find the
conditions on w when the angle a' >0 and when a' =0.
anonymous
 one year ago
5. A ball of mass m is suspended above the center of the rotating platform on the elastic spring with stiffness k and initial (nonstretched) length lo as shown. The opposite end of the spring is attached to the vertical pole fixed on axis of the platform. The platform starts to rotate with angular velocity w. What is the angle a' that the spring makes with the vertical? Consider all values of the angular velocity, from w=0 to w=inf and find the conditions on w when the angle a' >0 and when a' =0.

This Question is Open

maheshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.0can you show me the figure?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have attached the diagram here. It is the one labelled diagram five.

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.1i've had a play with this and i get \(\alpha\) for a given \(\omega \) to be \(tan \ \alpha = \frac{\omega^2 }{g}( l_{o} + \frac{mg}{k} + \epsilon )\) where \(\epsilon\) is the extra extension in the spring for that given \(\omega\). this makes sense as it implies that the thing rises but never gets to \(\alpha = \pi/2\) and at the same time \(\epsilon\) just gets bigger and bigger. not that the question makes that much sense to me really.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.