• anonymous
5. A ball of mass m is suspended above the center of the rotating platform on the elastic spring with stiffness k and initial (non-stretched) length lo as shown. The opposite end of the spring is attached to the vertical pole fixed on axis of the platform. The platform starts to rotate with angular velocity w. What is the angle a' that the spring makes with the vertical? Consider all values of the angular velocity, from w=0 to w=inf and find the conditions on w when the angle a' >0 and when a' =0.
  • Stacey Warren - Expert
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
  • katieb
I got my questions answered at in under 10 minutes. Go to now for free help!
  • maheshmeghwal9
can you show me the figure?
  • anonymous
I have attached the diagram here. It is the one labelled diagram five.
1 Attachment
  • IrishBoy123
i've had a play with this and i get \(\alpha\) for a given \(\omega \) to be \(tan \ \alpha = \frac{\omega^2 }{g}( l_{o} + \frac{mg}{k} + \epsilon )\) where \(\epsilon\) is the extra extension in the spring for that given \(\omega\). this makes sense as it implies that the thing rises but never gets to \(\alpha = \pi/2\) and at the same time \(\epsilon\) just gets bigger and bigger. not that the question makes that much sense to me really.

Looking for something else?

Not the answer you are looking for? Search for more explanations.