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anonymous
 one year ago
Factoring by groups
this quadratic equations
9x^2+13x4
anonymous
 one year ago
Factoring by groups this quadratic equations 9x^2+13x4

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0check if this right: 9x^2+13x4 9x^2+9x+4x4=0 9x(x+1) +4(x1)=0 what am I doing wrong? Why (x+1) and (x1) not equal?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.3you're close :) take a look here: dw:1436245778372:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you very much, you've been very helpful

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.3you're welcome ^_^!

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3sometimes: \(1 \times(9x^2+13x4) \) use ACmethod \(9 \times 4 = 36 \) identify 2 factors of 36 (AC) that adds to \(b \), (13): yes 9 and 4 \(1 \times (9x^2  9x  4x +4) \) \( 1 \times[9x (x1) 4(x1)] \)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Why did u multiply by 1?

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3to show you that there are different ways of making use of methods that you can come up with.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3now let us take it up a notch and treat x1 as one variable, say p \(1 [9x(p)  4(p)] \rightarrow 1(9xp  4p) \rightarrow p(9x4)\) rewrite: and I will put it back into original by undoing the multiplication of 1 to make you at ease \(p \rightarrow 1(x1) = (x+1)(9x4) \) WELCOME to the world of MATH

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have a another problem: −3x^2+17x−20 −3x^2+12x+5x−20 (−3x^2+12x)+(5x−20) Is this correct so far.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3let see what wolframalpha can tell us

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3try the AC method I showed you.

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3look at your coefficients A: B: C: \(3 \times 20 = 60 \) identify two factors of 60 that adds to \(b \) we have 12 and 5

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3this is a test of your arithmetic abilities mostly.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0(−3x^2+12x)+(5x−20) 3x(x4) +5(x−4) ok why GCF of (−3x^2+12x) is 3x not 3x. Answer: (3x + 5) ( x  4)

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3because one is negative, guy

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3you can't escape the negative

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh alright now I get it. Thanks for your help,sir. i appreciate it

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3do you get the ACmethod yet? look at the wolfram alpha attachment I showed you and learn some techniques from it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ac method is similar to factoring by grouping

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3depends on what it involves completing the square, ACmethod and quadratic formula they all become handy depending on the problem in chemistry such as in related rates or reaction rates, we use quadratic formula sometimes.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think this is the easiest method: https://www.youtube.com/watch?v=r1JAJfmRG5w&list=LLJjHKJ71EvI51FoDSRsSyg&index=5

nincompoop
 one year ago
Best ResponseYou've already chosen the best response.3it will depend on the problem you are given

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one last question: 9x^2+9x so the GCF of this binomial is 9x 9x(x1)

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.3that would be correct :)
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