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check if this right: -9x^2+13x-4 -9x^2+9x+4x-4=0 9x(-x+1) +4(x-1)=0 what am I doing wrong? Why (-x+1) and (x-1) not equal?
you're close :) take a look here: |dw:1436245778372:dw|
Thank you very much, you've been very helpful
you're welcome ^_^!
sometimes: \(-1 \times(-9x^2+13x-4) \) use AC-method \(9 \times 4 = 36 \) identify 2 factors of 36 (AC) that adds to \(|b| \), (13): yes 9 and 4 \(-1 \times (9x^2 - 9x - 4x +4) \) \( -1 \times[9x (x-1) -4(x-1)] \)
Why did u multiply by -1?
to show you that there are different ways of making use of methods that you can come up with.
now let us take it up a notch and treat x-1 as one variable, say p \(-1 [9x(p) - 4(p)] \rightarrow -1(9xp - 4p) \rightarrow -p(9x-4)\) rewrite: and I will put it back into original by undoing the multiplication of -1 to make you at ease \(-p \rightarrow -1(x-1) = (-x+1)(9x-4) \) WELCOME to the world of MATH
I have a another problem: −3x^2+17x−20 −3x^2+12x+5x−20 (−3x^2+12x)+(5x−20) Is this correct so far.
try the AC method I showed you.
look at your coefficients A: B: C: \(3 \times 20 = 60 \) identify two factors of 60 that adds to \(|b| \) we have 12 and 5
this is a test of your arithmetic abilities mostly.
(−3x^2+12x)+(5x−20) -3x(x-4) +5(x−4) ok why GCF of (−3x^2+12x) is -3x not 3x. Answer: (-3x + 5) ( x - 4)
because one is negative, guy
you can't escape the negative
oh alright now I get it. Thanks for your help,sir. i appreciate it
do you get the AC-method yet? look at the wolfram alpha attachment I showed you and learn some techniques from it.
Ac method is similar to factoring by grouping
depends on what it involves completing the square, AC-method and quadratic formula they all become handy depending on the problem in chemistry such as in related rates or reaction rates, we use quadratic formula sometimes.
I think this is the easiest method: https://www.youtube.com/watch?v=r1JAJfmRG5w&list=LLJjHKJ71EvI51FoDSRsSy-g&index=5
it will depend on the problem you are given
one last question: -9x^2+9x so the GCF of this binomial is -9x -9x(x-1)
that would be correct :)