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|dw:1436213647775:dw|
@Astrophysics do i just add 1 and bring the square eqal to the equilibrium point
?!?!?!?

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|dw:1436213934284:dw|
\(\color{blue}{\text{Originally Posted by}}\) @YumYum247 @Astrophysics do i just add 1 and bring the square eqal to the equilibrium point \(\color{blue}{\text{End of Quote}}\) Can you elaborate on this? Also what kind of interference is caused?
this type of interference is called destructive interference!!!
So if it is a destructive interference, the displacement must be 0 right?
What is your picture and what does it represent
by adding 1 i mean, when a crest and a trough head on collide with each other in this case when the triangle wave interferes with the rectangle wave, their wavelength would cancel out each other.... and the remaining crest/trough wold remain...in this case triangle
sorry i mean amplitude.
meant...-__-
because each amplitude is pulling on each other, the positive with negative and in this process they both reach the equilibrium point where none of them have any amplitude...
I'm not really sure, do they have the same amplitude?
similar to when when draw two NODES on a sine wave, when they interfere with each other, the way produces no sound at the equilibrium
Can you take an image of the question and post it
|dw:1436214505980:dw|
ok please wait....
1 Attachment
|dw:1436247128800:dw| so this is what we have initially
there are normally three scenarios, when two waves collide with each other , they produce supercrest....when two trough collide with each other they produce, supercrests and when two waves are identical in sizes, the resultant displacement is 0.
yes!!!
|dw:1436247232364:dw| so we note it's a destructive interference as they are going in the same direction, so we have to subtract them
yes !!
wait.......
add them
opposite*
sorry I mean opposite directions
your suppose to add the amplitude....i understand what your saying , since the rectangle is under the equilibrium point, so we have to subtract them.....but no, they are going to produce a height...
your rule only apples when the when the two shapes are merely identical....
you add them or subtract them, doesn't matter....cuz 1 + (-1) = 0 oe 1-1 = 0
i think since a rectangle is a half triangle, so when they collide with each other, the difference subtract out and the remaining trianlge stays...like i drew earlier...
|dw:1436215347405:dw|
Yup, you got the right thinking, one sec
because more mass is travelling in the opposite direction so when they collide with each other, amplitudes cancel out each other and the rest remains!!
Thank you infinite man!!! I Love you, i trlly do LOVE you, for helping me every day!!! :")
HAHAHAHA.....stay cute!!! :")
I'm still thinking about this problem, I'm not entirely sure it's 0, one sec.
|dw:1436215907399:dw|
Since i can't post another question while the previous one is still open, i'm just gunna ask you here... can you subtract lower frequency from higher frequency????? It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = |F2-F1| Fb = | 255 - 256| Gb = -1 Hz?!?!?!?!? Does it make nay sense?!?!!??
it says, if the freqency happens to be negative, yo just drop the sings and switch the sings???? is that true..????
I'm not entirely sure about your first question, I have forgotten a lot about superposition of waves, so I'll have to do some reading but when the pulses overlap the wave function is the sum of the different waves, and when the crests of the two align, the amplitude the difference between the individual amplitudes. For your second question, notice there's a reason we use absolute value signs :)
so the frequency is always positive? o_O
but when you have two frequencies that turn out to be negative, is that ok...never heard of a negative freqency??
The formula for beat is \[f_{beat} = f_a - f_b\] this is the beat frequency fa is the higher frequency
yes that's what i'm using right now, but when i plugin the given values i get a negative frequency.
It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = |F2-F1| Fb = | 255 - 256| Fb = -1 Hz?!?!?!?!?
255 - 256 = -1? o_O
Like I said, fa represents the higher frequency
i don't get it???? 8"(
yes but does a negative frequency make sense???
oh so....i got it....
so it doesn't matter what values are given to you, you plug-in the higher and subtract with lower......
Well, it doesn't matter, because we're using absolute value, that means all negative values turn positive so you're doing it right, you just have to notice it will still be positive.
|-12| = 12, |-100000| = 100000
oh, i didn't know that....Thanks MAN!!! OMG i'm crying here 8") Happy TEARS!!!
Haha :)
again thank you!!!
Np ^.^

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