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YumYum247
 one year ago
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YumYum247
 one year ago
8

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436213647775:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1@Astrophysics do i just add 1 and bring the square eqal to the equilibrium point

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436213934284:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\(\color{blue}{\text{Originally Posted by}}\) @YumYum247 @Astrophysics do i just add 1 and bring the square eqal to the equilibrium point \(\color{blue}{\text{End of Quote}}\) Can you elaborate on this? Also what kind of interference is caused?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1this type of interference is called destructive interference!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1So if it is a destructive interference, the displacement must be 0 right?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1What is your picture and what does it represent

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1by adding 1 i mean, when a crest and a trough head on collide with each other in this case when the triangle wave interferes with the rectangle wave, their wavelength would cancel out each other.... and the remaining crest/trough wold remain...in this case triangle

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1sorry i mean amplitude.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1because each amplitude is pulling on each other, the positive with negative and in this process they both reach the equilibrium point where none of them have any amplitude...

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I'm not really sure, do they have the same amplitude?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1similar to when when draw two NODES on a sine wave, when they interfere with each other, the way produces no sound at the equilibrium

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Can you take an image of the question and post it

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436214505980:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436247128800:dw so this is what we have initially

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1there are normally three scenarios, when two waves collide with each other , they produce supercrest....when two trough collide with each other they produce, supercrests and when two waves are identical in sizes, the resultant displacement is 0.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436247232364:dw so we note it's a destructive interference as they are going in the same direction, so we have to subtract them

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1sorry I mean opposite directions

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1your suppose to add the amplitude....i understand what your saying , since the rectangle is under the equilibrium point, so we have to subtract them.....but no, they are going to produce a height...

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1your rule only apples when the when the two shapes are merely identical....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1you add them or subtract them, doesn't matter....cuz 1 + (1) = 0 oe 11 = 0

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i think since a rectangle is a half triangle, so when they collide with each other, the difference subtract out and the remaining trianlge stays...like i drew earlier...

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436215347405:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yup, you got the right thinking, one sec

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1because more mass is travelling in the opposite direction so when they collide with each other, amplitudes cancel out each other and the rest remains!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Thank you infinite man!!! I Love you, i trlly do LOVE you, for helping me every day!!! :")

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1HAHAHAHA.....stay cute!!! :")

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I'm still thinking about this problem, I'm not entirely sure it's 0, one sec.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436215907399:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Since i can't post another question while the previous one is still open, i'm just gunna ask you here... can you subtract lower frequency from higher frequency????? It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = F2F1 Fb =  255  256 Gb = 1 Hz?!?!?!?!? Does it make nay sense?!?!!??

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1it says, if the freqency happens to be negative, yo just drop the sings and switch the sings???? is that true..????

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1I'm not entirely sure about your first question, I have forgotten a lot about superposition of waves, so I'll have to do some reading but when the pulses overlap the wave function is the sum of the different waves, and when the crests of the two align, the amplitude the difference between the individual amplitudes. For your second question, notice there's a reason we use absolute value signs :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so the frequency is always positive? o_O

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1but when you have two frequencies that turn out to be negative, is that ok...never heard of a negative freqency??

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1The formula for beat is \[f_{beat} = f_a  f_b\] this is the beat frequency fa is the higher frequency

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yes that's what i'm using right now, but when i plugin the given values i get a negative frequency.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = F2F1 Fb =  255  256 Fb = 1 Hz?!?!?!?!?

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Like I said, fa represents the higher frequency

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i don't get it???? 8"(

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1yes but does a negative frequency make sense???

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1oh so....i got it....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so it doesn't matter what values are given to you, you plugin the higher and subtract with lower......

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Well, it doesn't matter, because we're using absolute value, that means all negative values turn positive so you're doing it right, you just have to notice it will still be positive.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.112 = 12, 100000 = 100000

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1oh, i didn't know that....Thanks MAN!!! OMG i'm crying here 8") Happy TEARS!!!
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