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YumYum247

  • one year ago

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  1. YumYum247
    • one year ago
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    |dw:1436213647775:dw|

  2. YumYum247
    • one year ago
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    @Astrophysics do i just add 1 and bring the square eqal to the equilibrium point

  3. YumYum247
    • one year ago
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    ?!?!?!?

  4. YumYum247
    • one year ago
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    |dw:1436213934284:dw|

  5. Astrophysics
    • one year ago
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    \(\color{blue}{\text{Originally Posted by}}\) @YumYum247 @Astrophysics do i just add 1 and bring the square eqal to the equilibrium point \(\color{blue}{\text{End of Quote}}\) Can you elaborate on this? Also what kind of interference is caused?

  6. YumYum247
    • one year ago
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    this type of interference is called destructive interference!!!

  7. Astrophysics
    • one year ago
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    So if it is a destructive interference, the displacement must be 0 right?

  8. Astrophysics
    • one year ago
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    What is your picture and what does it represent

  9. YumYum247
    • one year ago
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    by adding 1 i mean, when a crest and a trough head on collide with each other in this case when the triangle wave interferes with the rectangle wave, their wavelength would cancel out each other.... and the remaining crest/trough wold remain...in this case triangle

  10. YumYum247
    • one year ago
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    sorry i mean amplitude.

  11. YumYum247
    • one year ago
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    meant...-__-

  12. YumYum247
    • one year ago
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    because each amplitude is pulling on each other, the positive with negative and in this process they both reach the equilibrium point where none of them have any amplitude...

  13. Astrophysics
    • one year ago
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    I'm not really sure, do they have the same amplitude?

  14. YumYum247
    • one year ago
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    similar to when when draw two NODES on a sine wave, when they interfere with each other, the way produces no sound at the equilibrium

  15. Astrophysics
    • one year ago
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    Can you take an image of the question and post it

  16. YumYum247
    • one year ago
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    |dw:1436214505980:dw|

  17. YumYum247
    • one year ago
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    ok please wait....

  18. YumYum247
    • one year ago
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  19. Astrophysics
    • one year ago
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    |dw:1436247128800:dw| so this is what we have initially

  20. YumYum247
    • one year ago
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    there are normally three scenarios, when two waves collide with each other , they produce supercrest....when two trough collide with each other they produce, supercrests and when two waves are identical in sizes, the resultant displacement is 0.

  21. YumYum247
    • one year ago
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    yes!!!

  22. Astrophysics
    • one year ago
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    |dw:1436247232364:dw| so we note it's a destructive interference as they are going in the same direction, so we have to subtract them

  23. YumYum247
    • one year ago
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    yes !!

  24. YumYum247
    • one year ago
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    wait.......

  25. YumYum247
    • one year ago
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    add them

  26. Astrophysics
    • one year ago
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    opposite*

  27. Astrophysics
    • one year ago
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    sorry I mean opposite directions

  28. YumYum247
    • one year ago
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    your suppose to add the amplitude....i understand what your saying , since the rectangle is under the equilibrium point, so we have to subtract them.....but no, they are going to produce a height...

  29. YumYum247
    • one year ago
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    your rule only apples when the when the two shapes are merely identical....

  30. YumYum247
    • one year ago
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    you add them or subtract them, doesn't matter....cuz 1 + (-1) = 0 oe 1-1 = 0

  31. YumYum247
    • one year ago
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    i think since a rectangle is a half triangle, so when they collide with each other, the difference subtract out and the remaining trianlge stays...like i drew earlier...

  32. YumYum247
    • one year ago
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    |dw:1436215347405:dw|

  33. Astrophysics
    • one year ago
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    Yup, you got the right thinking, one sec

  34. YumYum247
    • one year ago
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    because more mass is travelling in the opposite direction so when they collide with each other, amplitudes cancel out each other and the rest remains!!

  35. YumYum247
    • one year ago
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    Thank you infinite man!!! I Love you, i trlly do LOVE you, for helping me every day!!! :")

  36. YumYum247
    • one year ago
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    HAHAHAHA.....stay cute!!! :")

  37. Astrophysics
    • one year ago
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    I'm still thinking about this problem, I'm not entirely sure it's 0, one sec.

  38. YumYum247
    • one year ago
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    |dw:1436215907399:dw|

  39. YumYum247
    • one year ago
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    Since i can't post another question while the previous one is still open, i'm just gunna ask you here... can you subtract lower frequency from higher frequency????? It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = |F2-F1| Fb = | 255 - 256| Gb = -1 Hz?!?!?!?!? Does it make nay sense?!?!!??

  40. YumYum247
    • one year ago
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    it says, if the freqency happens to be negative, yo just drop the sings and switch the sings???? is that true..????

  41. Astrophysics
    • one year ago
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    I'm not entirely sure about your first question, I have forgotten a lot about superposition of waves, so I'll have to do some reading but when the pulses overlap the wave function is the sum of the different waves, and when the crests of the two align, the amplitude the difference between the individual amplitudes. For your second question, notice there's a reason we use absolute value signs :)

  42. YumYum247
    • one year ago
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    so the frequency is always positive? o_O

  43. YumYum247
    • one year ago
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    but when you have two frequencies that turn out to be negative, is that ok...never heard of a negative freqency??

  44. Astrophysics
    • one year ago
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    The formula for beat is \[f_{beat} = f_a - f_b\] this is the beat frequency fa is the higher frequency

  45. YumYum247
    • one year ago
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    yes that's what i'm using right now, but when i plugin the given values i get a negative frequency.

  46. YumYum247
    • one year ago
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    It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = |F2-F1| Fb = | 255 - 256| Fb = -1 Hz?!?!?!?!?

  47. YumYum247
    • one year ago
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    255 - 256 = -1? o_O

  48. Astrophysics
    • one year ago
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    Like I said, fa represents the higher frequency

  49. YumYum247
    • one year ago
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    i don't get it???? 8"(

  50. YumYum247
    • one year ago
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    yes but does a negative frequency make sense???

  51. YumYum247
    • one year ago
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    oh so....i got it....

  52. YumYum247
    • one year ago
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    so it doesn't matter what values are given to you, you plug-in the higher and subtract with lower......

  53. Astrophysics
    • one year ago
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    Well, it doesn't matter, because we're using absolute value, that means all negative values turn positive so you're doing it right, you just have to notice it will still be positive.

  54. Astrophysics
    • one year ago
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    |-12| = 12, |-100000| = 100000

  55. YumYum247
    • one year ago
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    oh, i didn't know that....Thanks MAN!!! OMG i'm crying here 8") Happy TEARS!!!

  56. Astrophysics
    • one year ago
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    Haha :)

  57. YumYum247
    • one year ago
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    again thank you!!!

  58. Astrophysics
    • one year ago
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    Np ^.^

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