YumYum247 one year ago 8

1. YumYum247

|dw:1436213647775:dw|

2. YumYum247

@Astrophysics do i just add 1 and bring the square eqal to the equilibrium point

3. YumYum247

?!?!?!?

4. YumYum247

|dw:1436213934284:dw|

5. Astrophysics

$$\color{blue}{\text{Originally Posted by}}$$ @YumYum247 @Astrophysics do i just add 1 and bring the square eqal to the equilibrium point $$\color{blue}{\text{End of Quote}}$$ Can you elaborate on this? Also what kind of interference is caused?

6. YumYum247

this type of interference is called destructive interference!!!

7. Astrophysics

So if it is a destructive interference, the displacement must be 0 right?

8. Astrophysics

What is your picture and what does it represent

9. YumYum247

by adding 1 i mean, when a crest and a trough head on collide with each other in this case when the triangle wave interferes with the rectangle wave, their wavelength would cancel out each other.... and the remaining crest/trough wold remain...in this case triangle

10. YumYum247

sorry i mean amplitude.

11. YumYum247

meant...-__-

12. YumYum247

because each amplitude is pulling on each other, the positive with negative and in this process they both reach the equilibrium point where none of them have any amplitude...

13. Astrophysics

I'm not really sure, do they have the same amplitude?

14. YumYum247

similar to when when draw two NODES on a sine wave, when they interfere with each other, the way produces no sound at the equilibrium

15. Astrophysics

Can you take an image of the question and post it

16. YumYum247

|dw:1436214505980:dw|

17. YumYum247

18. YumYum247

19. Astrophysics

|dw:1436247128800:dw| so this is what we have initially

20. YumYum247

there are normally three scenarios, when two waves collide with each other , they produce supercrest....when two trough collide with each other they produce, supercrests and when two waves are identical in sizes, the resultant displacement is 0.

21. YumYum247

yes!!!

22. Astrophysics

|dw:1436247232364:dw| so we note it's a destructive interference as they are going in the same direction, so we have to subtract them

23. YumYum247

yes !!

24. YumYum247

wait.......

25. YumYum247

26. Astrophysics

opposite*

27. Astrophysics

sorry I mean opposite directions

28. YumYum247

your suppose to add the amplitude....i understand what your saying , since the rectangle is under the equilibrium point, so we have to subtract them.....but no, they are going to produce a height...

29. YumYum247

your rule only apples when the when the two shapes are merely identical....

30. YumYum247

you add them or subtract them, doesn't matter....cuz 1 + (-1) = 0 oe 1-1 = 0

31. YumYum247

i think since a rectangle is a half triangle, so when they collide with each other, the difference subtract out and the remaining trianlge stays...like i drew earlier...

32. YumYum247

|dw:1436215347405:dw|

33. Astrophysics

Yup, you got the right thinking, one sec

34. YumYum247

because more mass is travelling in the opposite direction so when they collide with each other, amplitudes cancel out each other and the rest remains!!

35. YumYum247

Thank you infinite man!!! I Love you, i trlly do LOVE you, for helping me every day!!! :")

36. YumYum247

HAHAHAHA.....stay cute!!! :")

37. Astrophysics

38. YumYum247

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39. YumYum247

Since i can't post another question while the previous one is still open, i'm just gunna ask you here... can you subtract lower frequency from higher frequency????? It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = |F2-F1| Fb = | 255 - 256| Gb = -1 Hz?!?!?!?!? Does it make nay sense?!?!!??

40. YumYum247

it says, if the freqency happens to be negative, yo just drop the sings and switch the sings???? is that true..????

41. Astrophysics

I'm not entirely sure about your first question, I have forgotten a lot about superposition of waves, so I'll have to do some reading but when the pulses overlap the wave function is the sum of the different waves, and when the crests of the two align, the amplitude the difference between the individual amplitudes. For your second question, notice there's a reason we use absolute value signs :)

42. YumYum247

so the frequency is always positive? o_O

43. YumYum247

but when you have two frequencies that turn out to be negative, is that ok...never heard of a negative freqency??

44. Astrophysics

The formula for beat is $f_{beat} = f_a - f_b$ this is the beat frequency fa is the higher frequency

45. YumYum247

yes that's what i'm using right now, but when i plugin the given values i get a negative frequency.

46. YumYum247

It says "Tuning fork 1(256Hz) is sounded with tuning fork 2 (255 Hz). What is the frequency?!?!?!?! Fb = |F2-F1| Fb = | 255 - 256| Fb = -1 Hz?!?!?!?!?

47. YumYum247

255 - 256 = -1? o_O

48. Astrophysics

Like I said, fa represents the higher frequency

49. YumYum247

i don't get it???? 8"(

50. YumYum247

yes but does a negative frequency make sense???

51. YumYum247

oh so....i got it....

52. YumYum247

so it doesn't matter what values are given to you, you plug-in the higher and subtract with lower......

53. Astrophysics

Well, it doesn't matter, because we're using absolute value, that means all negative values turn positive so you're doing it right, you just have to notice it will still be positive.

54. Astrophysics

|-12| = 12, |-100000| = 100000

55. YumYum247

oh, i didn't know that....Thanks MAN!!! OMG i'm crying here 8") Happy TEARS!!!

56. Astrophysics

Haha :)

57. YumYum247

again thank you!!!

58. Astrophysics

Np ^.^