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anonymous
 one year ago
verify the trigonometric equation by substituting identities to match the right hand side with the left hand side:
(sinx / 1cosx) + (sinx / 1+cosx) = 2cscx
anonymous
 one year ago
verify the trigonometric equation by substituting identities to match the right hand side with the left hand side: (sinx / 1cosx) + (sinx / 1+cosx) = 2cscx

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0looks like this \[\frac{ sinx }{ 1cosx } + \frac{ sinx }{ 1+cosx }=2cscx\] been stuck on this forever...

maheshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.1on left hand side take L.C.M.

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2start with your left hand side :) hint: You'll want put the two fractions over the same denominator .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so, would i get them both under 1cos^2x?

maheshmeghwal9
 one year ago
Best ResponseYou've already chosen the best response.1It Becomes \[\frac{ sinx(1+cosx)+sinx(1cosx) }{ \sin^2x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright then do I distribute sin?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2distribute sinx :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2sinx }{ \sin^2x }\] like this?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2then from there, you can simplify the fraction and you'll get the answer (RHS) :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so how do I simplify this, Sorry! this is where i have been stuck at.

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2oh you can divide the numerator and denominator by sinx

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so is it 2/sinx? And then just change it to csc?

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2likeee: dw:1436251446732:dw

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2and yes that's correct :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ahh ok THANK YOUUU!!!!!!!!!!

butterflydreamer
 one year ago
Best ResponseYou've already chosen the best response.2no problem :)!!
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