## wampominater one year ago verify the trigonometric equation by substituting identities to match the right hand side with the left hand side: (sinx / 1-cosx) + (sinx / 1+cosx) = 2cscx

1. wampominater

looks like this $\frac{ sinx }{ 1-cosx } + \frac{ sinx }{ 1+cosx }=2cscx$ been stuck on this forever...

2. maheshmeghwal9

on left hand side take L.C.M.

3. butterflydreamer

start with your left hand side :) hint: You'll want put the two fractions over the same denominator .

4. wampominater

so, would i get them both under 1-cos^2x?

5. wampominater

over*

6. butterflydreamer

correct:)

7. maheshmeghwal9

It Becomes $\frac{ sinx(1+cosx)+sinx(1-cosx) }{ \sin^2x }$

8. wampominater

alright then do I distribute sin?

9. butterflydreamer

yyeeepp

10. butterflydreamer

distribute sinx :)

11. wampominater

$\frac{ 2sinx }{ \sin^2x }$ like this?

12. maheshmeghwal9

yes

13. butterflydreamer

then from there, you can simplify the fraction and you'll get the answer (RHS) :)

14. wampominater

Ok so how do I simplify this, Sorry! this is where i have been stuck at.

15. butterflydreamer

oh you can divide the numerator and denominator by sinx

16. wampominater

so is it 2/sinx? And then just change it to csc?

17. butterflydreamer

likeee: |dw:1436251446732:dw|

18. butterflydreamer

and yes that's correct :)

19. wampominater

ahh ok THANK YOUUU!!!!!!!!!!

20. butterflydreamer

no problem :)!!