YumYum247
  • YumYum247
t
Physics
katieb
  • katieb
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YumYum247
  • YumYum247
@Astrophysics Any idea master?!?!?!?!
Astrophysics
  • Astrophysics
This has to do with intensity of sound which are expressed in decibels where the formula is represented as \[\beta = (10 dB)\log \frac{ I }{ I_0 }\] where \[I_0\] is the reference intensity which is a constant, given as \[10^{-12} \frac{ W }{ m^2 }\] which is our threshold actually, so if we used are formula and got that, it would mean the level is 0 dB. From what I recall approximately 85 dB is safe, and 90 isn't the worse either. See if you can figure the intensity out for what you're given and compare it, 180 dB is really insane.
YumYum247
  • YumYum247
yes!!!!! :"D

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YumYum247
  • YumYum247
thank you 8-> :") lets see if you figure that out
YumYum247
  • YumYum247
"8->"
Astrophysics
  • Astrophysics
Lol, I'm not sure whether it's suppose to be something appropriate or not xD
YumYum247
  • YumYum247
it means "infinite and continue"
Astrophysics
  • Astrophysics
\[\huge \lim_{:") \rightarrow \infty}\] this is how we do it in math
YumYum247
  • YumYum247
LOL, i'm not that good at Latex :")
Astrophysics
  • Astrophysics
Haha, it's ok :p
YumYum247
  • YumYum247
again thank you.

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