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YumYum247
 one year ago
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YumYum247
 one year ago
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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@Astrophysics Any idea master?!?!?!?!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1This has to do with intensity of sound which are expressed in decibels where the formula is represented as \[\beta = (10 dB)\log \frac{ I }{ I_0 }\] where \[I_0\] is the reference intensity which is a constant, given as \[10^{12} \frac{ W }{ m^2 }\] which is our threshold actually, so if we used are formula and got that, it would mean the level is 0 dB. From what I recall approximately 85 dB is safe, and 90 isn't the worse either. See if you can figure the intensity out for what you're given and compare it, 180 dB is really insane.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0thank you 8> :") lets see if you figure that out

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Lol, I'm not sure whether it's suppose to be something appropriate or not xD

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0it means "infinite and continue"

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[\huge \lim_{:") \rightarrow \infty}\] this is how we do it in math

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0LOL, i'm not that good at Latex :")
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