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- YumYum247

r

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- YumYum247

@Astrophysics Your highness, please guide me through this problem, Thanks in advance!!! :")

- YumYum247

i'm getting 257Hz

- YumYum247

V = d/t = 12/6 = 2Hz
Fb = F1-F2
2Hz = f1- 255Hz
2Hz = f1+255Hz
+255Hz = f1
257Hz = f1
or other possibility
Fb = F1+ F2
2Hz = F1 - 255Hz
-253Hz = F1

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## More answers

- YumYum247

257Hz?

- Astrophysics

How does distance over time give you 2Hz??

- Astrophysics

Can you fix your question as well

- YumYum247

LOL....:"D
F = N/Change in time
F = 12 cycles/ 6 sec
F = 2cycles persecond!!!

- Astrophysics

What is this? `It is sounded again with tuning fir 2`

- YumYum247

##### 1 Attachment

- YumYum247

that question is the follow up of the previous question.....

- YumYum247

the beat efficiency was 1Hz

- YumYum247

for the second part, they tie the first tuning fork 1 (256Hz) to reduce it's freqency and sound it with fork number 2 (255Hz).

- YumYum247

"FORK 2"|dw:1436222090799:dw|

- Astrophysics

\[f = \frac{ 12 beats }{ 6 \sec } = 2 hz\]

- YumYum247

so is that the "NEW FREQUENCY" of FORK 1?????

- YumYum247

NO that's the beat frequency!!!

- YumYum247

when you hear woo woo woo woo in the wave, that's that....

- Astrophysics

\[2Hz = |f_2 - 255 Hz|\] so we have 2 cases then \[\pm 2Hz = f_2 - 255Hz\]
now solve for both cases what do you get

- YumYum247

i did, there are two possibilities, first is 257Hz and the other is -253Hz

- Astrophysics

You should say 253 and 257, remember what I told you earlier about absolute values

- YumYum247

but it doesn't make sense for a sec because when you tie a tuning fork with a rubber it's frequency shold drop, not increase!!!!

- YumYum247

am i right.

- Astrophysics

Yeah, so which one is it then?

- YumYum247

let's say i have a tuning fork and i tie it with a rubber band.....and sound it with another fork, shouldn't its freqency drop because it's arms are tied together

- Astrophysics

Yes, we already know the frequency for 1 reduces, that's why we have to pick the right case :)

- YumYum247

|dw:1436222480252:dw|

- YumYum247

so one case gives me a higher frequency and the second one gives me a negative freqency. which one is it

- YumYum247

-253Hz

- Astrophysics

Again, I've told you this many times, we can't have the negative frequency, remember the absolute value signs.

- YumYum247

i know but the other option gives us a higher freqency than the original frequency....

- Astrophysics

You should be saying 253 Hz, not -253 Hz, you can't have a negative frequency

- YumYum247

initially fork 1 was produing a 256Hz but after tieing it with a rubber band, it produces a frequency of 257Hz ?!?!?!?

- YumYum247

Oh MY GOD.....are you cereal?

- YumYum247

so that's why...LOL :"D
i feel stpid for a sec

- YumYum247

so the freak is 253Hz cuz we can't have a negative freak.....
it even applies here???

- Astrophysics

\[2 = |f_2 - 255|\]
This means \[\pm 2 = f_2 - 255\] the first case \[+2 = f_2 - 255 \implies 255+2 = f_2 \implies 257 = f_2\] the other case gives us \[-2 = f_2 - 255 \implies f_2 = 255-2 = 253 Hz\]

- YumYum247

253 is the right... i got it...!!! LOL Luv you man, i'd have never learnt that with out you!!

- Astrophysics

No problem, frequency can never be negative, just remember the absolute value makes the negative into a positive.

- YumYum247

got it boss!!!!!

- Astrophysics

You can learn more about it here: http://www.mathsisfun.com/numbers/absolute-value.html

- YumYum247

aight thanks

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