## YumYum247 one year ago r

1. YumYum247

2. YumYum247

i'm getting 257Hz

3. YumYum247

V = d/t = 12/6 = 2Hz Fb = F1-F2 2Hz = f1- 255Hz 2Hz = f1+255Hz +255Hz = f1 257Hz = f1 or other possibility Fb = F1+ F2 2Hz = F1 - 255Hz -253Hz = F1

4. YumYum247

257Hz?

5. Astrophysics

How does distance over time give you 2Hz??

6. Astrophysics

Can you fix your question as well

7. YumYum247

LOL....:"D F = N/Change in time F = 12 cycles/ 6 sec F = 2cycles persecond!!!

8. Astrophysics

What is this? It is sounded again with tuning fir 2

9. YumYum247

10. YumYum247

that question is the follow up of the previous question.....

11. YumYum247

the beat efficiency was 1Hz

12. YumYum247

for the second part, they tie the first tuning fork 1 (256Hz) to reduce it's freqency and sound it with fork number 2 (255Hz).

13. YumYum247

"FORK 2"|dw:1436222090799:dw|

14. Astrophysics

$f = \frac{ 12 beats }{ 6 \sec } = 2 hz$

15. YumYum247

so is that the "NEW FREQUENCY" of FORK 1?????

16. YumYum247

NO that's the beat frequency!!!

17. YumYum247

when you hear woo woo woo woo in the wave, that's that....

18. Astrophysics

$2Hz = |f_2 - 255 Hz|$ so we have 2 cases then $\pm 2Hz = f_2 - 255Hz$ now solve for both cases what do you get

19. YumYum247

i did, there are two possibilities, first is 257Hz and the other is -253Hz

20. Astrophysics

You should say 253 and 257, remember what I told you earlier about absolute values

21. YumYum247

but it doesn't make sense for a sec because when you tie a tuning fork with a rubber it's frequency shold drop, not increase!!!!

22. YumYum247

am i right.

23. Astrophysics

Yeah, so which one is it then?

24. YumYum247

let's say i have a tuning fork and i tie it with a rubber band.....and sound it with another fork, shouldn't its freqency drop because it's arms are tied together

25. Astrophysics

Yes, we already know the frequency for 1 reduces, that's why we have to pick the right case :)

26. YumYum247

|dw:1436222480252:dw|

27. YumYum247

so one case gives me a higher frequency and the second one gives me a negative freqency. which one is it

28. YumYum247

-253Hz

29. Astrophysics

Again, I've told you this many times, we can't have the negative frequency, remember the absolute value signs.

30. YumYum247

i know but the other option gives us a higher freqency than the original frequency....

31. Astrophysics

You should be saying 253 Hz, not -253 Hz, you can't have a negative frequency

32. YumYum247

initially fork 1 was produing a 256Hz but after tieing it with a rubber band, it produces a frequency of 257Hz ?!?!?!?

33. YumYum247

Oh MY GOD.....are you cereal?

34. YumYum247

so that's why...LOL :"D i feel stpid for a sec

35. YumYum247

so the freak is 253Hz cuz we can't have a negative freak..... it even applies here???

36. Astrophysics

$2 = |f_2 - 255|$ This means $\pm 2 = f_2 - 255$ the first case $+2 = f_2 - 255 \implies 255+2 = f_2 \implies 257 = f_2$ the other case gives us $-2 = f_2 - 255 \implies f_2 = 255-2 = 253 Hz$

37. YumYum247

253 is the right... i got it...!!! LOL Luv you man, i'd have never learnt that with out you!!

38. Astrophysics

No problem, frequency can never be negative, just remember the absolute value makes the negative into a positive.

39. YumYum247

got it boss!!!!!

40. Astrophysics