A community for students.
Here's the question you clicked on:
 0 viewing
YumYum247
 one year ago
r
YumYum247
 one year ago
r

This Question is Closed

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1@Astrophysics Your highness, please guide me through this problem, Thanks in advance!!! :")

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1V = d/t = 12/6 = 2Hz Fb = F1F2 2Hz = f1 255Hz 2Hz = f1+255Hz +255Hz = f1 257Hz = f1 or other possibility Fb = F1+ F2 2Hz = F1  255Hz 253Hz = F1

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1How does distance over time give you 2Hz??

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Can you fix your question as well

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1LOL....:"D F = N/Change in time F = 12 cycles/ 6 sec F = 2cycles persecond!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1What is this? `It is sounded again with tuning fir 2`

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1that question is the follow up of the previous question.....

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1the beat efficiency was 1Hz

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1for the second part, they tie the first tuning fork 1 (256Hz) to reduce it's freqency and sound it with fork number 2 (255Hz).

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1"FORK 2"dw:1436222090799:dw

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[f = \frac{ 12 beats }{ 6 \sec } = 2 hz\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so is that the "NEW FREQUENCY" of FORK 1?????

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1NO that's the beat frequency!!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1when you hear woo woo woo woo in the wave, that's that....

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[2Hz = f_2  255 Hz\] so we have 2 cases then \[\pm 2Hz = f_2  255Hz\] now solve for both cases what do you get

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i did, there are two possibilities, first is 257Hz and the other is 253Hz

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You should say 253 and 257, remember what I told you earlier about absolute values

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1but it doesn't make sense for a sec because when you tie a tuning fork with a rubber it's frequency shold drop, not increase!!!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yeah, so which one is it then?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1let's say i have a tuning fork and i tie it with a rubber band.....and sound it with another fork, shouldn't its freqency drop because it's arms are tied together

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Yes, we already know the frequency for 1 reduces, that's why we have to pick the right case :)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1dw:1436222480252:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so one case gives me a higher frequency and the second one gives me a negative freqency. which one is it

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1Again, I've told you this many times, we can't have the negative frequency, remember the absolute value signs.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1i know but the other option gives us a higher freqency than the original frequency....

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You should be saying 253 Hz, not 253 Hz, you can't have a negative frequency

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1initially fork 1 was produing a 256Hz but after tieing it with a rubber band, it produces a frequency of 257Hz ?!?!?!?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1Oh MY GOD.....are you cereal?

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so that's why...LOL :"D i feel stpid for a sec

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1so the freak is 253Hz cuz we can't have a negative freak..... it even applies here???

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1\[2 = f_2  255\] This means \[\pm 2 = f_2  255\] the first case \[+2 = f_2  255 \implies 255+2 = f_2 \implies 257 = f_2\] the other case gives us \[2 = f_2  255 \implies f_2 = 2552 = 253 Hz\]

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1253 is the right... i got it...!!! LOL Luv you man, i'd have never learnt that with out you!!

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1No problem, frequency can never be negative, just remember the absolute value makes the negative into a positive.

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1You can learn more about it here: http://www.mathsisfun.com/numbers/absolutevalue.html
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.