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anonymous

  • one year ago

50 ml of a 0.1 mol L-1 solution of silver nitrate is reacted with excess sodium chloride solution.Calculate the mass of silver chloride that will be precipitated

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  1. anonymous
    • one year ago
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    Could you help me with this question @peachpi

  2. anonymous
    • one year ago
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    **I am using mm to denote the molar mass of AgCl. \[AgNO_3~(aq)+NaCl~(aq) \rightarrow AgCl~(s) + NaNO_3~(aq)\] The first thing you have to do is use the given concentration and volume to find the moles of AgNO3. \[molarity~[M]=\frac{ amount~[moles] }{ volume~[L] }\] You may find it easier to calculate that first, and then use dimensional analysis. |dw:1436275516483:dw| Alternatively, you can use the equation as part of the conversion process, as shown below |dw:1436274420922:dw|

  3. anonymous
    • one year ago
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    **I missed a 0 in the top drawing. The conversion should start with 0.005 mol AgNO3 as calculated

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