## anonymous one year ago 50 ml of a 0.1 mol L-1 solution of silver nitrate is reacted with excess sodium chloride solution.Calculate the mass of silver chloride that will be precipitated

1. anonymous

Could you help me with this question @peachpi

2. anonymous

**I am using mm to denote the molar mass of AgCl. $AgNO_3~(aq)+NaCl~(aq) \rightarrow AgCl~(s) + NaNO_3~(aq)$ The first thing you have to do is use the given concentration and volume to find the moles of AgNO3. $molarity~[M]=\frac{ amount~[moles] }{ volume~[L] }$ You may find it easier to calculate that first, and then use dimensional analysis. |dw:1436275516483:dw| Alternatively, you can use the equation as part of the conversion process, as shown below |dw:1436274420922:dw|

3. anonymous

**I missed a 0 in the top drawing. The conversion should start with 0.005 mol AgNO3 as calculated