50 ml of a 0.1 mol L-1 solution of silver nitrate is reacted with excess sodium chloride solution.Calculate the mass of silver chloride that will be precipitated

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50 ml of a 0.1 mol L-1 solution of silver nitrate is reacted with excess sodium chloride solution.Calculate the mass of silver chloride that will be precipitated

Chemistry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Could you help me with this question @peachpi
**I am using mm to denote the molar mass of AgCl. \[AgNO_3~(aq)+NaCl~(aq) \rightarrow AgCl~(s) + NaNO_3~(aq)\] The first thing you have to do is use the given concentration and volume to find the moles of AgNO3. \[molarity~[M]=\frac{ amount~[moles] }{ volume~[L] }\] You may find it easier to calculate that first, and then use dimensional analysis. |dw:1436275516483:dw| Alternatively, you can use the equation as part of the conversion process, as shown below |dw:1436274420922:dw|
**I missed a 0 in the top drawing. The conversion should start with 0.005 mol AgNO3 as calculated

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