A community for students.

Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

anonymous

  • one year ago

(08.03)Solve the system of equations and choose the correct answer from the list of options. x − y = 7 y = 3x + 12 2 over 19 comma 2 over 33 negative 2 over 19 comma negative 33 over 2 negative 19 over 2 comma negative 33 over 2 19 over 2 comma 33 over 2

  • This Question is Closed
  1. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    someone help please

  2. Haseeb96
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    There are two equations We call first equation as eq#1 and 2nd equation as eq#2 x-y=7.................eq#1 y=3x+12 .............eq#2 now what you have to do Just plug y's value of eq#2 into equation 1 at the place of y you will get this one x-3x-12 =7 -2x = 19 x= -19/2 now put x= -19/2 into eq#1 and get the value of y -19/2 -y=7 y=-19/2 -7 y=-19-14/2 y=-33/2 so your (x,y)= (-19/2, -33/2)

  3. Haseeb96
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 1

    so, C is correct answer

  4. anonymous
    • one year ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Haseeb96 is correct

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy

Your question is ready. Sign up for free to start getting answers.

spraguer (Moderator)
5 → View Detailed Profile

is replying to Can someone tell me what button the professor is hitting...

23

  • Teamwork 19 Teammate
  • Problem Solving 19 Hero
  • You have blocked this person.
  • ✔ You're a fan Checking fan status...

Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.

This is the testimonial you wrote.
You haven't written a testimonial for Owlfred.