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Barrelracer17

  • one year ago

Indicate the equation of the given line in standard form. The line containing the altitude to the hypotenuse of a right triangle whose vertices are P(-1, 1), Q(3, 5), and R(5, -5).

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  1. anonymous
    • one year ago
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    do a reply guys so i can medal it!!

  2. anonymous
    • one year ago
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    bye

  3. Barrelracer17
    • one year ago
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    ??

  4. welshfella
    • one year ago
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    rough diagram |dw:1436273146483:dw|

  5. Barrelracer17
    • one year ago
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    whats the equation to it?

  6. welshfella
    • one year ago
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    the hypotenuse is QR so the altitude would be PR

  7. welshfella
    • one year ago
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    use the standard form y - y1 = m(x - x1) where m = slope and (x1,y1) is a point on the line.

  8. welshfella
    • one year ago
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    the coordinates of the points a re P (-1,1) and R(5,-5) m = (-5-1)/(5-(-1))

  9. welshfella
    • one year ago
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    plug those values into the general equation

  10. welshfella
    • one year ago
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    what do you get m (-5-1)/ (5-(-1)) = ?

  11. Barrelracer17
    • one year ago
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    -6/6

  12. welshfella
    • one year ago
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    right which = ?

  13. welshfella
    • one year ago
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    -1 right?

  14. Barrelracer17
    • one year ago
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    yeah

  15. Barrelracer17
    • one year ago
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    @MMMercado please help

  16. anonymous
    • one year ago
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    cool dude im here, hmm lets see

  17. Barrelracer17
    • one year ago
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    Please help

  18. anonymous
    • one year ago
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    ;c well firstly whatcha lookin for, wording is werid lol

  19. Barrelracer17
    • one year ago
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    i need an equation to the line with the points above in standard form

  20. radar
    • one year ago
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    Formula for straight line: Slope-intercept form: y = mx + b Point-slope form: \[y - y _{1} = m(x-x _{1})\] Standard form: ax + by = c General form: ax + by + c = 0

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