Indicate the equation of the given line in standard form. The line containing the altitude to the hypotenuse of a right triangle whose vertices are P(-1, 1), Q(3, 5), and R(5, -5).

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Indicate the equation of the given line in standard form. The line containing the altitude to the hypotenuse of a right triangle whose vertices are P(-1, 1), Q(3, 5), and R(5, -5).

Geometry
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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do a reply guys so i can medal it!!
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rough diagram |dw:1436273146483:dw|
whats the equation to it?
the hypotenuse is QR so the altitude would be PR
use the standard form y - y1 = m(x - x1) where m = slope and (x1,y1) is a point on the line.
the coordinates of the points a re P (-1,1) and R(5,-5) m = (-5-1)/(5-(-1))
plug those values into the general equation
what do you get m (-5-1)/ (5-(-1)) = ?
-6/6
right which = ?
-1 right?
yeah
@MMMercado please help
cool dude im here, hmm lets see
Please help
;c well firstly whatcha lookin for, wording is werid lol
i need an equation to the line with the points above in standard form
Formula for straight line: Slope-intercept form: y = mx + b Point-slope form: \[y - y _{1} = m(x-x _{1})\] Standard form: ax + by = c General form: ax + by + c = 0

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