Barrelracer17
  • Barrelracer17
Indicate the equation of the given line in standard form. The line containing the altitude to the hypotenuse of a right triangle whose vertices are P(-1, 1), Q(3, 5), and R(5, -5).
Geometry
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
do a reply guys so i can medal it!!
anonymous
  • anonymous
bye
Barrelracer17
  • Barrelracer17
??

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welshfella
  • welshfella
rough diagram |dw:1436273146483:dw|
Barrelracer17
  • Barrelracer17
whats the equation to it?
welshfella
  • welshfella
the hypotenuse is QR so the altitude would be PR
welshfella
  • welshfella
use the standard form y - y1 = m(x - x1) where m = slope and (x1,y1) is a point on the line.
welshfella
  • welshfella
the coordinates of the points a re P (-1,1) and R(5,-5) m = (-5-1)/(5-(-1))
welshfella
  • welshfella
plug those values into the general equation
welshfella
  • welshfella
what do you get m (-5-1)/ (5-(-1)) = ?
Barrelracer17
  • Barrelracer17
-6/6
welshfella
  • welshfella
right which = ?
welshfella
  • welshfella
-1 right?
Barrelracer17
  • Barrelracer17
yeah
Barrelracer17
  • Barrelracer17
@MMMercado please help
anonymous
  • anonymous
cool dude im here, hmm lets see
Barrelracer17
  • Barrelracer17
Please help
anonymous
  • anonymous
;c well firstly whatcha lookin for, wording is werid lol
Barrelracer17
  • Barrelracer17
i need an equation to the line with the points above in standard form
radar
  • radar
Formula for straight line: Slope-intercept form: y = mx + b Point-slope form: \[y - y _{1} = m(x-x _{1})\] Standard form: ax + by = c General form: ax + by + c = 0

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