## anonymous one year ago a feather is dropped onto the surface of the moon. how far will the feather have fallen if it reaches the surface in 9.00 seconds? given g: on moon is -1.63m/s2

• This Question is Open
1. anonymous

$d=v_0t+\frac{ 1 }{ 2 }at^2$ where $$v_0=0$$ and $$a=g$$ so the equation becomes $d=\frac{ 1 }{ 2 }gt^2$ plug in your time and gravity