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anonymous

  • one year ago

Prove: 4 13file:///C:/Users/Student/Desktop/pics%20for%20plato/2a4de8556f04bfa775832f871dfdea80

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  1. sleepyhead314
    • one year ago
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    @TheBleep Hey there and Welcome to OpenStudy! :) you can attach files with the blue "Attach File" button below :)

  2. anonymous
    • one year ago
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  3. anonymous
    • one year ago
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    and thxs :)

  4. sleepyhead314
    • one year ago
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    hmm I can't seem to open the file? :-/ if it is a picture, perhaps you can try ScreenShotting it instead :)

  5. anonymous
    • one year ago
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    Proof: Statement Reason 1. p || q given 2. 4 12 For parallel lines cut by a transversal, corresponding angles are congruent. 3. 4. 9 13 For parallel lines cut by a transversal, corresponding angles are congruent. 5. 4 13 Transitive Property of Congruence i have to find the missing step

  6. sleepyhead314
    • one year ago
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    if 4 = 12 _______ 9 = 13 then 4 = 13 they are combining the two somehow if it is transitive property if a=b and b=c, then a=c the middle of that should be 12 = 9 (I think)

  7. anonymous
    • one year ago
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    well if its not the right answer which im pretty sure it is thx for ur help :)

  8. anonymous
    • one year ago
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    i got another question if you can help if you want :)

  9. sleepyhead314
    • one year ago
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    I can try :) it's a little tough without a picture xD

  10. anonymous
    • one year ago
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    yea xD

  11. anonymous
    • one year ago
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    What is the missing reason in the proof? segment addition Congruent Segments Theorem Transitive Property of Equality Subtraction Property of Equality

  12. anonymous
    • one year ago
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    maybe you can now xD im figuring this stuff out :)

  13. sleepyhead314
    • one year ago
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    what they did was substitute CF = EB into AE + EB = CF + FD to get AE + CF = CF + FD then - CF -CF subtracted CF from both sides ------------------------------- AE = FD ^^^ Subtraction Property of Equality would be my best guess

  14. anonymous
    • one year ago
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    thx :D

  15. sleepyhead314
    • one year ago
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    if you need any more help, just tag me when I'm online :) @sleepyhead314

  16. anonymous
    • one year ago
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    kk

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