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mmend98

  • one year ago

How can 1/3x – 2 = y and 1/4x + 11 = y be set up as a system of equations? 3y – x = –6 4y – x = 44 3y + x = –6 4y + x = 44 3y – 3x = –6 4y – 4x = 44 3y + 3x = –6 4y + 4x = 44

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  1. mmend98
    • one year ago
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    @ganeshie8

  2. mmend98
    • one year ago
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    @Michele_Laino

  3. anonymous
    • one year ago
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    convert them both to standard form.

  4. Michele_Laino
    • one year ago
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    for example, your first equation can be rewritten as follows: \[\frac{x}{3} - 2 = y \to x - 6 = 3y\] where I have multiplied both sides by 3

  5. mmend98
    • one year ago
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    and thats all? @Michele_Laino @dirtydishr4g

  6. Michele_Laino
    • one year ago
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    yes! Please multiply the both sides of your second equation by 4, what do you get?

  7. Michele_Laino
    • one year ago
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    Hint: you should get this: \[\frac{x}{4} + 11 = y \to x + 44 = 4y\]

  8. mmend98
    • one year ago
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    I get x+44=4y

  9. mmend98
    • one year ago
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    @Michele_Laino

  10. Michele_Laino
    • one year ago
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    that's right!

  11. Michele_Laino
    • one year ago
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    now, if I subtract x, I get: \[x + 44 - x = 4y - x\] please simplify

  12. mmend98
    • one year ago
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    4y-x=44? @Michele_Laino

  13. Michele_Laino
    • one year ago
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    that's right!

  14. Michele_Laino
    • one year ago
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    now I do the same with your first equation: \[x - 6 - x = 3y - x\] please simplify

  15. mmend98
    • one year ago
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    So the answer would be A? 3y – x = –6 4y – x = 44

  16. Michele_Laino
    • one year ago
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    that's right!

  17. mmend98
    • one year ago
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    Thank you. @Michele_Laino

  18. Michele_Laino
    • one year ago
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    :)

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