How can 1/3x – 2 = y and 1/4x + 11 = y be set up as a system of equations? 3y – x = –6 4y – x = 44 3y + x = –6 4y + x = 44 3y – 3x = –6 4y – 4x = 44 3y + 3x = –6 4y + 4x = 44

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How can 1/3x – 2 = y and 1/4x + 11 = y be set up as a system of equations? 3y – x = –6 4y – x = 44 3y + x = –6 4y + x = 44 3y – 3x = –6 4y – 4x = 44 3y + 3x = –6 4y + 4x = 44

Mathematics
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convert them both to standard form.

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Other answers:

for example, your first equation can be rewritten as follows: \[\frac{x}{3} - 2 = y \to x - 6 = 3y\] where I have multiplied both sides by 3
yes! Please multiply the both sides of your second equation by 4, what do you get?
Hint: you should get this: \[\frac{x}{4} + 11 = y \to x + 44 = 4y\]
I get x+44=4y
that's right!
now, if I subtract x, I get: \[x + 44 - x = 4y - x\] please simplify
that's right!
now I do the same with your first equation: \[x - 6 - x = 3y - x\] please simplify
So the answer would be A? 3y – x = –6 4y – x = 44
that's right!
Thank you. @Michele_Laino
:)

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