Henry's law constant for solubility of methane in benzene is 4.27 x 10^5 at constant temperature. Calculate solubility of methane at 760mm of Hg pressure at the same temperature.

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Henry's law constant for solubility of methane in benzene is 4.27 x 10^5 at constant temperature. Calculate solubility of methane at 760mm of Hg pressure at the same temperature.

Chemistry
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Member Henry's law formula?
S=KP where k is Henry's constant and p is the pressure or partial pressure of the gas

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\( p = k_H X\) Where kH = 4.27 x 105 mm, p = 760 mm of Hg, and X is the molar fraction.
i did the same but my textbook says that its not the answer! Answer in the textbook may be wrong
anyways thanks for help!

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