(Fan and Medal will be given)! Help with Area Find the area of the image below:

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(Fan and Medal will be given)! Help with Area Find the area of the image below:

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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1 Attachment
hint: the area of your geometrical shape, is given by the sum of the areas of these triangles:
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so what exactly do I do ? Im not too well with this benchmark D: .

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Other answers:

we have: area of triangle ABE: \[A = \frac{{BE \times AK}}{2} = \frac{{8 \times 5}}{2} = ...\]
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so 8 * 5 = 40 an d 40 divided by 2 is 20 .
ok!
area of triangle CDE: \[A = \frac{{CE \times DK}}{2} = \frac{{5 \times 4}}{2} = ...\]
5 * 4 equals 20 and 20 divded by 2 is 10
ok!
finally: area of triangle CBE: \[A = \frac{{BE \times CE}}{2} = \frac{{8 \times 5}}{2} = ...\]
8*5 equals 40 again divided by two is 20 :D
ok!
so total area is: 20+10+20=...
50
yes! nevertheless that answer is not an option of yours
wow , :/
my reasoning is right, I don't understand maybe is there a scale factor, for your drawing?
namely, how many units are the area of the littlest square, of your drawing?
can u help me find the perimeter for it please michele , D: its not area , its perimeter. sorry ive made a mistake
ok!
then we have to apply the theorem of Pitagora repeatedly
so we can write this: \[BC = \sqrt {C{E^2} + B{E^2}} = \sqrt {{5^2} + {8^2}} = \sqrt {25 + 64} = ...?\]
ok is that is 89
yes! and what is:sqrt(89)=...?
9.433
that's right!
now we have: \[AB = \sqrt {A{H^2} + B{H^2}} = \sqrt {{5^2} + {6^2}} = \sqrt {25 + 36} = ...?\]
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its 61
and what is: sqrt(61)=...?
the square root of 61is 7.81
perfect!
:D
now we have: \[AE = \sqrt {A{H^2} + E{H^2}} = \sqrt {{5^2} + {2^2}} = \sqrt {25 + 4} = ...?\]
25 plus 4 is 29 and the square root of 29 is 5.38
yes! correct!
next we have: \[ED = \sqrt {K{D^2} + E{K^2}} = \sqrt {{4^2} + {2^2}} = \sqrt {16 + 4} = ...?\]
16 + 4 = 20 and square root of 20 is 4.47
ok!
finally, we have: \[CD = \sqrt {K{D^2} + C{K^2}} = \sqrt {{4^2} + {3^2}} = \sqrt {16 + 9} = ...?\]
5 :D
perfect!
so the requested perimeter, is: BC+AB+AE+ED+CD= =9.43+7.81+5.39+4.47+5=...?
32.1 :D yipee
that's right! :)
Thank you sooo much :D i will be adding these into my notes thanks a lot I appreciate it ! God bless.
Thanks!! :) :)
Yw :)
:)

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