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anonymous
 one year ago
(Fan and Medal will be given)!
Help with Area
Find the area of the image below:
anonymous
 one year ago
(Fan and Medal will be given)! Help with Area Find the area of the image below:

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Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2hint: the area of your geometrical shape, is given by the sum of the areas of these triangles:

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what exactly do I do ? Im not too well with this benchmark D: .

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2we have: area of triangle ABE: \[A = \frac{{BE \times AK}}{2} = \frac{{8 \times 5}}{2} = ...\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so 8 * 5 = 40 an d 40 divided by 2 is 20 .

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2area of triangle CDE: \[A = \frac{{CE \times DK}}{2} = \frac{{5 \times 4}}{2} = ...\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05 * 4 equals 20 and 20 divded by 2 is 10

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2finally: area of triangle CBE: \[A = \frac{{BE \times CE}}{2} = \frac{{8 \times 5}}{2} = ...\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.08*5 equals 40 again divided by two is 20 :D

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so total area is: 20+10+20=...

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! nevertheless that answer is not an option of yours

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2my reasoning is right, I don't understand maybe is there a scale factor, for your drawing?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2namely, how many units are the area of the littlest square, of your drawing?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me find the perimeter for it please michele , D: its not area , its perimeter. sorry ive made a mistake

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2then we have to apply the theorem of Pitagora repeatedly

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so we can write this: \[BC = \sqrt {C{E^2} + B{E^2}} = \sqrt {{5^2} + {8^2}} = \sqrt {25 + 64} = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2yes! and what is:sqrt(89)=...?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2now we have: \[AB = \sqrt {A{H^2} + B{H^2}} = \sqrt {{5^2} + {6^2}} = \sqrt {25 + 36} = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2and what is: sqrt(61)=...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the square root of 61is 7.81

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2now we have: \[AE = \sqrt {A{H^2} + E{H^2}} = \sqrt {{5^2} + {2^2}} = \sqrt {25 + 4} = ...?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.025 plus 4 is 29 and the square root of 29 is 5.38

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2next we have: \[ED = \sqrt {K{D^2} + E{K^2}} = \sqrt {{4^2} + {2^2}} = \sqrt {16 + 4} = ...?\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.016 + 4 = 20 and square root of 20 is 4.47

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2finally, we have: \[CD = \sqrt {K{D^2} + C{K^2}} = \sqrt {{4^2} + {3^2}} = \sqrt {16 + 9} = ...?\]

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2so the requested perimeter, is: BC+AB+AE+ED+CD= =9.43+7.81+5.39+4.47+5=...?

Michele_Laino
 one year ago
Best ResponseYou've already chosen the best response.2that's right! :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you sooo much :D i will be adding these into my notes thanks a lot I appreciate it ! God bless.
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