## Aizhalee one year ago (Fan and Medal will be given)! Help with Area Find the area of the image below:

1. aizhalee

2. Michele_Laino

hint: the area of your geometrical shape, is given by the sum of the areas of these triangles:

3. aizhalee

so what exactly do I do ? Im not too well with this benchmark D: .

4. Michele_Laino

we have: area of triangle ABE: $A = \frac{{BE \times AK}}{2} = \frac{{8 \times 5}}{2} = ...$

5. aizhalee

so 8 * 5 = 40 an d 40 divided by 2 is 20 .

6. Michele_Laino

ok!

7. Michele_Laino

area of triangle CDE: $A = \frac{{CE \times DK}}{2} = \frac{{5 \times 4}}{2} = ...$

8. aizhalee

5 * 4 equals 20 and 20 divded by 2 is 10

9. Michele_Laino

ok!

10. Michele_Laino

finally: area of triangle CBE: $A = \frac{{BE \times CE}}{2} = \frac{{8 \times 5}}{2} = ...$

11. aizhalee

8*5 equals 40 again divided by two is 20 :D

12. Michele_Laino

ok!

13. Michele_Laino

so total area is: 20+10+20=...

14. aizhalee

50

15. Michele_Laino

yes! nevertheless that answer is not an option of yours

16. aizhalee

wow , :/

17. Michele_Laino

my reasoning is right, I don't understand maybe is there a scale factor, for your drawing?

18. Michele_Laino

namely, how many units are the area of the littlest square, of your drawing?

19. aizhalee

can u help me find the perimeter for it please michele , D: its not area , its perimeter. sorry ive made a mistake

20. Michele_Laino

ok!

21. Michele_Laino

then we have to apply the theorem of Pitagora repeatedly

22. Michele_Laino

so we can write this: $BC = \sqrt {C{E^2} + B{E^2}} = \sqrt {{5^2} + {8^2}} = \sqrt {25 + 64} = ...?$

23. aizhalee

ok is that is 89

24. Michele_Laino

yes! and what is:sqrt(89)=...?

25. aizhalee

9.433

26. Michele_Laino

that's right!

27. Michele_Laino

now we have: $AB = \sqrt {A{H^2} + B{H^2}} = \sqrt {{5^2} + {6^2}} = \sqrt {25 + 36} = ...?$

28. Michele_Laino

29. aizhalee

its 61

30. Michele_Laino

and what is: sqrt(61)=...?

31. aizhalee

the square root of 61is 7.81

32. Michele_Laino

perfect!

33. aizhalee

:D

34. Michele_Laino

now we have: $AE = \sqrt {A{H^2} + E{H^2}} = \sqrt {{5^2} + {2^2}} = \sqrt {25 + 4} = ...?$

35. aizhalee

25 plus 4 is 29 and the square root of 29 is 5.38

36. Michele_Laino

yes! correct!

37. Michele_Laino

next we have: $ED = \sqrt {K{D^2} + E{K^2}} = \sqrt {{4^2} + {2^2}} = \sqrt {16 + 4} = ...?$

38. aizhalee

16 + 4 = 20 and square root of 20 is 4.47

39. Michele_Laino

ok!

40. Michele_Laino

finally, we have: $CD = \sqrt {K{D^2} + C{K^2}} = \sqrt {{4^2} + {3^2}} = \sqrt {16 + 9} = ...?$

41. aizhalee

5 :D

42. Michele_Laino

perfect!

43. Michele_Laino

so the requested perimeter, is: BC+AB+AE+ED+CD= =9.43+7.81+5.39+4.47+5=...?

44. aizhalee

32.1 :D yipee

45. Michele_Laino

that's right! :)

46. aizhalee

Thank you sooo much :D i will be adding these into my notes thanks a lot I appreciate it ! God bless.

47. Michele_Laino

Thanks!! :) :)

48. aizhalee

Yw :)

49. Michele_Laino

:)