anonymous
  • anonymous
I can't figure this one out.. MEDAL AND FAN FOR ANYONE WHO CAN UN-CONFUZZLE ME!! For the function f(x) = –(x + 1)2 + 4, identify the vertex, domain, and range.
Mathematics
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anonymous
  • anonymous
I can't figure this one out.. MEDAL AND FAN FOR ANYONE WHO CAN UN-CONFUZZLE ME!! For the function f(x) = –(x + 1)2 + 4, identify the vertex, domain, and range.
Mathematics
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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Loser66
  • Loser66
Where are you stuck?
anonymous
  • anonymous
mostly the vertex
Loser66
  • Loser66
open parentheses, what do you have for f(x) ?

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anonymous
  • anonymous
f(x)=-x+1^2+4
Loser66
  • Loser66
nnnnnnnnnnnnnope
Loser66
  • Loser66
\(f(x) = -(x+1)^2 +4\) redo, please. Use Foil
anonymous
  • anonymous
-x+5? after you simplify ?
anonymous
  • anonymous
How do you find out the range aswell I vaguely remember
Loser66
  • Loser66
\((x+1)^2 =(x+1)(x+1)\) ,using Foil to open parentheses
anonymous
  • anonymous
Oh ya I forgot you had to do that with squared binomials
anonymous
  • anonymous
X^2+2x+1
Loser66
  • Loser66
Yup, don't forget, before them, you have - sign, after them you have +4 now, put all in, what do you get for f(x) ??
anonymous
  • anonymous
Where did you get the +4 from?
Loser66
  • Loser66
From the original problem.
anonymous
  • anonymous
Oh ok, did I mess up the foil? You said something about a negative and when I plugged 4 into \[x ^{2}+2x+1 \] I got 25 and that's not one of the choices for the y-coordinate and it doesn't really make sense
Loser66
  • Loser66
NOOOOOOOOOPe
Loser66
  • Loser66
\(f(x) = \huge \color{red}{-} (x+1)^2 +4\\~~~~~~~~~~=\huge\color{red}{-} (x^2+2x+1)+4\\=\huge -x^2-2x-1+4\) ok??
Loser66
  • Loser66
hey!!! YES or NO?
anonymous
  • anonymous
OOHHH
anonymous
  • anonymous
YES got it :) but how bought the range? Ik the domains gunna be all real numbers
Loser66
  • Loser66
wait, simplify it, please.
Loser66
  • Loser66
don't know??? why?? -1+4 =?
anonymous
  • anonymous
3?
Loser66
  • Loser66
yes, so that \(f(x) =-x^2-2x+3\) right?
Loser66
  • Loser66
From this, the REAL process starts.
Loser66
  • Loser66
what are a, b, c on it?
Loser66
  • Loser66
a=? b=? c=?
anonymous
  • anonymous
a=-1 b=-2 c=3
Loser66
  • Loser66
yup, hence the vertex has x-coordinate is \(x= -b/2a\) , hence x =??
anonymous
  • anonymous
x=4
Loser66
  • Loser66
\(x=-\dfrac{b}{2a}=-\dfrac{-2}{2*(-1)}=??\)
anonymous
  • anonymous
1
anonymous
  • anonymous
so the vertex is 1,4?
anonymous
  • anonymous
TY FOR HELPING ME FIGURE HAT PART OUT :)))) but how do I know what the range is going to be?
Loser66
  • Loser66
to it, when you have vertex, and the parabola is downward, hence the range is from - infinitive to y-coordinate of the vertex.

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