Trig integral, is it possible to solve this way?

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Trig integral, is it possible to solve this way?

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So for this I integrated but did not plug in the 4 sec theta. Is that legal?
Well, I mean I know it is odd to do, but the basic format of the answer should be correct, right?
show your work, please

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Ok. Give me a sec to type.
Ignoring the whole 4 sec stuff |dw:1436283835864:dw|
I'm still going
|dw:1436283910258:dw|
How can you go from the original one to it? |dw:1436284026292:dw|
Oh no. Maybe that is my problem. I forget that sqrt.
Wait.
Ignore that.
They assign you to use x =4sec (theta) . Why don't you use it?
|dw:1436284192993:dw|
I was hoping I could do the base integration first and kinda cheat.
|dw:1436284294104:dw|
I mean @Loser66 I'm also checking and getting this http://www.wolframalpha.com/input/?i=Integrate+%281%29%2F%28x%5E2sqrt%28x%5E2-16%29%29%2C+x+%3D+4+secant+theta so I kinda think im right?
lol http://www.wolframalpha.com/input/?i=Integrate+%281%29%2F%284+secant+theta%5E2sqrt%284+secant+theta%5E2-16%29%29 So yea im pretty confident.
internet is awful cutting out
ok , you are right, but I would like to know how can you turn from sin (sec^- (x/4) ) to that result. To make sure that you can get it by hand, not cheat from wolfram
From|dw:1436284669272:dw|
yes
Give me a bit
|dw:1436284793682:dw|
I don't get |dw:1436284904403:dw|
Hint: \(x = 4 sec (theta) = \dfrac{4}{cos (theta)}\) \(\sqrt{x^2+16}=4tan(theta) =\dfrac{4sin(theta)}{cos(theta)}\) see the link?
Oh!
You aint nothing but a hound dog barking all the time you aint never caught a rabbit and you aint no friend of mine
That is not directed at you loser 66, but at calc 2
hey, what do you mean by "You aint nothing but a hound dog barking all the time you aint never caught a rabbit and you aint no friend of mine"?? are you insulting me?? because I am trying to help you out?? OMG
Hahahahahahah nooo!! Elvis man!

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