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Help in Algebra 1 question Screenshot below!

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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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:))) Part B and C are my struggles
Does that have an affect on the overall answer for part A because I figured that I just didn't find it relevant to state.
@inowalst plz help!

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ok, it looks like your answer for A is mostly correct. Your domain for this function would be [0, 6] because those are the relevant x values. It looks like you used y-values for each part. The function is increasing on (0, 3) and decreasing on (3,6).
Omg thank you soo much :D
C would be which tho cuz its rate of change isn't that time and speed or something?
^^That was a correction for A. For b, it's asking for the domain (x-values) if the minimum of the function was $60. You want to look find the two points on the graph where y = 60, and use them to be the domain for B.
would it be then (60,1) AND (60,5) ?
x comes first, so (1, 60) and (5, 60). Which means the domain would be [1, 5]
For C, any function can have a rate of change. It just has different meanings for different applications. For this function rate of change is amount of profit gained or lost for each increases in price
Ok and also another question regarding A you wrote (0, 3) wouldn't that be (0,30) because the 3 isn't shown?
It's kind of hard to keep track of when you're starting out. Domains/ranges are represented by intervals, which uses the same notation as points. (0, 3) in part A is an interval, meaning the function is increasing from x = 0 to x = 3. It's not the point (0, 3).
does that make sense?
ohhh :D
yes it does make sense when its not meaning a point :P
ok. for part C do you need help finding the rate of change?
Yes i do cuz honestly I dont understand rate of change what so ever i figured its just the number but its a lot more confusing than it seems for me lol if that makes sense
let me ask you this, do you know how to find the slope given 2 points?
\[m=\frac{ y_2-y_1 }{ x_2-x_1 }\] look familiar?
isn't the slope y=mx+b
10-5 m= _____ 5/3 6-3
y=mx+b y= 5/3+b
right?
y= mx+b is the equation of a line. The slope is just m. Your problem has a parabola. But you can use the same formula to find rate of change. They want rate of change from 3 to 5. When x = 3, y = 120 When x = 5, y = 60 \[m=\frac{ 60-120 }{ 5-3 }=\frac{ -60 }{ 2 }=-30\]
so the rate of change is -30
ahhhhhh :D :D :D :D Ok That makes a lot more sense thank you so so so much for all your help and I will give u medals so check ur notifications thanks so much :D
you're welcome :)

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