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AmTran_Bus
 one year ago
Limit question?
AmTran_Bus
 one year ago
Limit question?

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AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436286205012:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Um. Here are my choices but Im getting DNE

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0What in the world someone help! http://www.wolframalpha.com/input/?i=limit+as+x+approaches+0+%28e%5Ex6%29%2Fsin+4x

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0The problem does not say from the left or right!!!!!!!!! So my DNE is right but what do I do?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3\(\large\color{slate}{\displaystyle\lim_{x \rightarrow ~0}\frac{e^x6}{\sin(4x)}}\) ?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0would l'hopitals rule be helpful here?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Good thought. Let me try it

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3it is not 0/0 when you plug in x=0

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0right  only the denoiminator = 0 l'hopitals no help

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Oh yea, must be inf/inf or 0/0

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0as x approaches 0 sin 4x approaches 0 and e^x  6 approaches 5 so can we then say that the limit is  infinity?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0 approaching from above 0

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3you are right, the limit actually doesn't exst.

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Yea, thats what has thrown me off for a long time. But wolfram treats it as 0+ and 0 and and the answer choices have both neg inf and pos inf

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3even one sides limits diverge

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3when you get a limit that is equal to +∞ or ∞, that means the limit does NOT exist. (It is infinite  not limited)

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0But it is an ans choice!

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3Well, for two sides limit, it DNE

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3from the right side it is ∞, from the left side it is ∞

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0dumb problem and ans choices

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3do you have an answer choice does not exist?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.0yes near the y axis the graph looks like dw:1436287092439:dw

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella so do you agree DNE?

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Well thanks for all your help! I may email prof

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Well, I asked on yahoo ans and they said inf. I just dont see it but gotta mark something @hartnn @SolomonZelman @welshfella

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1limit shouldn't exist sin 4x is negative when x<0 and it is positive when x>0 hence Left hand limit would not = right hand limit

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0I agree hartnn. Just these ans choices giving fit.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3ok, maybe the question is a little bit different?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3Are you sure it is exactly saying \(\Large\color{slate}{\displaystyle\lim_{x \rightarrow ~0}\frac{e^x6}{\sin(4x)}}\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3well, then this limit doesn't exist.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3I mean if limit=∞ or ∞ it doesn't exist (either way)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1people saying infinity are assuming that sin4x = 0 e^x 6 will be negative

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3yeah, should have noticed that:)

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0I'm here! So is it inf after all?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1no lol, the limit is still DNE. In yahoo answer, they might have said inf as they might have assumed sin4x =0 ... that was my point, but sin 4x is not actually 0

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3well, if you take the limit of sin(4x) as x→0 alone, then it is 0

AmTran_Bus
 one year ago
Best ResponseYou've already chosen the best response.0Story of my life...

hartnn
 one year ago
Best ResponseYou've already chosen the best response.1why would you do that lol...

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.31 D, XD = (1+x)D

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3the limit is indeterminate, beause you are trying to divide by zero

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3technically u r...

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.3when you divide by a number that approaches 0 from the right, you get ∞, and when you divide by a number that approaches 0 from the left, you get ∞. if the divident is positive. In this case divident is negative, so it is the other way around. when you divide by a number that approaches 0 from the right, you get ∞, and when you divide by a number that approaches 0 from the left, you get ∞. And if you take a 2sides limit (as in your case), you shouldn't get just ∞ or ∞.....
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