## anonymous one year ago Help in Algebra 1 Screenshot Below!!

1. anonymous

2. anonymous

@Owlcoffee :D :D:D can u help?

3. Owlcoffee

On the first part you are asked to use the discriminant to describe the solutions of the quadratic equation. As you might know, a quadratic equation can be solved using the general formula or "bhaskara's formula": $x=\frac{ -b \pm \sqrt{b^2-4ac} }{ 2a }$ But this formula has a part we call "discriminant" and as you might have guessed, it is everything inside the radical, the discriminant is often notated with the capital greek letter "delta"; $\Delta = b^2 - 4ac$ The discriminant gives away the behavior of the solution of a quadratic equation, therefore, there are 3 possible scenarios: $1) \Delta >0$ If the discriminant is greater than zero, meaning, a positive number, the quadratic equation will have two solutions x1, x2. $2) \Delta =0$ If the discriminant is equal to zero, then the quadratic equation will have one solution and graphically means that the parabola formed is tangent to the x-axis. $3) \Delta <0$ if the discriminant is negative, the quadratic equation will have no real solutions and graphically means that the parabola formed does not cut the x-axis.

4. anonymous

ahhh that makes sense :D so what would B and C be then?

5. Owlcoffee

Well, you can use the general formula to solve one, and use factoriation to solve the other.

6. anonymous

ok :D Thanks :)