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anonymous

  • one year ago

how to calculate launch velocity and angle given: t (sec)=2.36 h (m)= 1.5 ∆x (m)= 5.4 a (m/s )= -9.8 m/s^2

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  1. anonymous
    • one year ago
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    what does your h refer to?

  2. anonymous
    • one year ago
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    h refers to the height of where the object was launched from.

  3. anonymous
    • one year ago
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    |dw:1436294737806:dw|

  4. anonymous
    • one year ago
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    thank you so much!!

  5. anonymous
    • one year ago
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    if the a is -9.8, then will the displcement must also be in negative?

  6. anonymous
    • one year ago
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    Your X displacement (displacement along the horizontal axis) is going to be positive. The Y displacement (displacement along the vertical axis) is going to be negative because you are starting from height "h" above the ground and the object ends up on the ground. So yes, you are correct that the net displacement in the Y direction is -1.5m.

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