how to calculate launch velocity and angle given: t (sec)=2.36 h (m)= 1.5 ∆x (m)= 5.4 a (m/s )= -9.8 m/s^2

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how to calculate launch velocity and angle given: t (sec)=2.36 h (m)= 1.5 ∆x (m)= 5.4 a (m/s )= -9.8 m/s^2

Physics
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what does your h refer to?
h refers to the height of where the object was launched from.
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thank you so much!!
if the a is -9.8, then will the displcement must also be in negative?
Your X displacement (displacement along the horizontal axis) is going to be positive. The Y displacement (displacement along the vertical axis) is going to be negative because you are starting from height "h" above the ground and the object ends up on the ground. So yes, you are correct that the net displacement in the Y direction is -1.5m.

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