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anonymous

  • one year ago

Calculate the change internal energy (ΔE) for a system that is giving off 45.0 kJ of heat and is performing 855 J of work on the surroundings.

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  1. anonymous
    • one year ago
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    I thought it would be -44.1 but the answer key says -45.9

  2. anonymous
    • one year ago
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    try using mcat and the rest of the question

  3. aaronq
    • one year ago
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    giving off heat is negative and so is doing work. \(\Delta U=q+w=-45000~J+(-855~J)\)

  4. Photon336
    • one year ago
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    If work is done on the system it's positive; if it's done to on the surroundings it's negative. if heat leaves the system q <0 if heat enters system q >0 total internal energy delta E = q+ w

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