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anonymous
 one year ago
Please help*** Proving Trigonometric Identities
anonymous
 one year ago
Please help*** Proving Trigonometric Identities

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436290113123:dw

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2\(\large\color{black}{ \displaystyle 12\sin^2\theta=2\cos^2\theta1 }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2\(\large\color{black}{ \displaystyle 12\sin^2\theta=2\cos^2\theta1 }\) knowing that \(\large\color{blue}{ \displaystyle 1=\sin^2\theta+\cos^2\theta }\) \(\large\color{black}{ \displaystyle (\sin^2\theta+\cos^2\theta)2\sin^2\theta=2\cos^2\theta(\sin^2\theta+\cos^2\theta) }\) \(\large\color{black}{ \displaystyle \sin^2\theta+\cos^2\theta2\sin^2\theta=2\cos^2\theta\sin^2\theta\cos^2\theta }\) now, finish and simplify.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm still lost @SolomonZelman

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2you can't add/subtract like terms?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0would it be sin^2 (theta) + cos^2(theta) = cos^2(theta)  sin^2 (theta) @SolomonZelman

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2sin²θ  2sin²θ = ?

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.2so, your left side is \(\large\color{black}{ \displaystyle \sin^2\theta+\cos^2\theta }\) and the right side is \(\large\color{black}{ \displaystyle \cos^2\theta\sin^2\theta }\) (the right side is same as left side, so yes, it is an identity)
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