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anonymous
 one year ago
a student in greece discovers a pottery bowl that contains 62% of it's original amount of c14 find the age of the bowl to the nearest year
anonymous
 one year ago
a student in greece discovers a pottery bowl that contains 62% of it's original amount of c14 find the age of the bowl to the nearest year

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IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0you'll need the half life if C14 to start with

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05730 is the half life of c14

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no, i have the formula N=N0e^kt

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0adding some colour to the decay equation: \(N(t)=N_oe^{kt}\) or \(N(t)/N_o= e^{kt}\) it is decay so k= minus number the half life tells you when \(N(t)/N_o= 0.5\) but \(e^{0.0001 * 5730} \ne 0.5\) you need \(k = 1.21 \times 10^{4}\) so find t for \(N(t)/N_o= 0.62\) lots of clues in there :p

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I really don't understand it at all would you mind going step by step to solve it?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0OK lets say a long long time ago you started with \(N_o\) atoms of C14. [C_14 atoms are unstable and undergo \(\beta \) decay. \(\mathrm{~^{14}_{6}C}\rightarrow\mathrm{~^{14}_{7}N}+ e^ + \bar{\nu}_e\)] so the amount N you have at any time t is given by the equation you have \(N(t) = N_o e^{kt}\), an exponential decay equation. if at time t you have 62% left, then \(N(t)/N_o = 0.62\) your job is to find t, knowing that \(k=−1.21×10^{−4} \) and \(0.62 = e^{kt}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would I go about solving that? My calculator won't do it

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0use your brain, its much more powerful :p thought about take logs of both sides?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0natural logarithms....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i have no clue what that is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm pretty sure k=0.000121

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and you told me .62 is e^kt

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0well that's very surprising. your teacher should not be asking you to do stuff like this unless they want you to spend all night guessing the answer. all i can say is that to calc, say, natural log 5, you find the \(ln\) button on your calculator and go for it using the number 5 and if you have something like \(e^z\), then \(ln \ ( e^z) = z\) so you can take log on both sides to unravel this....... and that's a close as i can get to actually doing it for you, in fact i may well be too close already, and that will get me in trouble in these parts :(
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