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anonymous
 one year ago
What is the value of x?
Round to the nearest tenth.
anonymous
 one year ago
What is the value of x? Round to the nearest tenth.

This Question is Closed

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle a^2+b^2=c^2 }\) where c is the hypotenuse of a right triangle, and a & b are the legs.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1Would you then agree with the following set up (to find x)? \(\large\color{black}{ \displaystyle 12^2+x^2=22^2 }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1ok, then tell me what x is going to equal (and disregard the negative x solution)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1it is not 12+x=22 then it would have been correct, BUT///

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1it is 12²+x²=22²

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1first, you have to simplify the powers.

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle 12^2+x^2=22^2 }\) \(\large\color{black}{ \displaystyle 144+x^2=484 }\) when you subtract 144 from both sides, you get: \(\large\color{black}{ \displaystyle x^2=340 }\)

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1then take the square root of both sides.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what's the final answer? @SolomonZelman

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@SolomonZelman i running out of time please

SolomonZelman
 one year ago
Best ResponseYou've already chosen the best response.1\(\large\color{black}{ \displaystyle x^2=340 }\) \(\large\color{black}{ \displaystyle \sqrt{x^2}=\sqrt{340} }\) \(\large\color{black}{ \displaystyle x=\pm \sqrt{340} }\) exclude the negative result, as a side can't be negagive. \(\large\color{black}{ \displaystyle x=\sqrt{340} }\) \(\large\color{black}{ \displaystyle x=\sqrt{4\times 85} }\) \(\large\color{black}{ \displaystyle x=2\sqrt{85} }\)
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