## anonymous one year ago Which is an equation in point-slope form of the line that passes through the points (4,5) and (-3, -1)

1. anonymous

We need to find the slope first so $\frac{ y_2-y_1 }{ x_2-x_1 }$

2. anonymous

Can you find the slope using that formula please? ^_^

3. anonymous

$11\frac{ ? }{ ? }-8$

4. anonymous

oops sorry! 11 over -8

5. anonymous

Not quite I will set up the problem for you :) $\huge~\rm~\frac{ -1-5 }{ -3-4 }=slope$

6. anonymous

-6 over -7?

7. anonymous

yes :) Alright next step is to pick a point lets got with (4,5) Are you fimilar with this formula? $\huge~\rm~y-y_1=m(x-x_1)$

8. anonymous

not really

9. anonymous

$\huge~\rm~y-y_1=m(x-x_1)$ M=slope=6/7<--lets keep it positive : ) x1=4 y1=5 Can you sub in the values please? :)

10. anonymous

5-5=6/7(4-4)

11. anonymous

No quite we do not need to plug in the values for the varibles that have no number $\huge~\rm~y-y_1=m(x-x_1)$ M=slope=6/7<--lets keep it positive : ) x1=4 y1=5 $\huge~\rm~y-5=\frac{ 6 }{ 7 }(x-4)$

12. anonymous

i suck at this stuff!

13. anonymous

Thats all it is buddy! :) You are doing just fine

14. anonymous

is that the answer? its not one of my choices

15. anonymous

What are the choices?

16. anonymous

Hello?

17. anonymous

in here! sorry!

18. pooja195

I can finish up :) looks like they left

19. anonymous

y+1=6/5(x+3) y+1=6/7(x+3) y-1=6/7(x-3) y+3=7/6(x+1)

20. pooja195

oh ok the only problem is that they used the wrong point not hard to fix we always need to use the 2nd point so (-3,-1) and we get y+1=6/7(x+3) We get "+" because a negative and a negative touching each other make a postive :) understood?

21. anonymous

i do! thank you! could you help me with a few more?

22. anonymous

linear inequality graph Which is an equation of the given line in standard form? A. –11x + 6y = –13 B. –6x +11y = 13 C. –6x + 11y = –13 D. –6x + 7y = –17

23. pooja195

wow i suck at standered for @Jaynator495

24. anonymous
25. Jaynator495

Cannot help because you are from k12, sorry about this... you can ask indirect questions but NO test questions...