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anonymous
 one year ago
Which is an equation in pointslope form of the line that passes through the points (4,5) and (3, 1)
anonymous
 one year ago
Which is an equation in pointslope form of the line that passes through the points (4,5) and (3, 1)

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We need to find the slope first so \[\frac{ y_2y_1 }{ x_2x_1 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you find the slope using that formula please? ^_^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[11\frac{ ? }{ ? }8\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops sorry! 11 over 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not quite I will set up the problem for you :) \[\huge~\rm~\frac{ 15 }{ 34 }=slope\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes :) Alright next step is to pick a point lets got with (4,5) Are you fimilar with this formula? \[\huge~\rm~yy_1=m(xx_1)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\huge~\rm~yy_1=m(xx_1)\] M=slope=6/7<lets keep it positive : ) x1=4 y1=5 Can you sub in the values please? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No quite we do not need to plug in the values for the varibles that have no number \[\huge~\rm~yy_1=m(xx_1)\] M=slope=6/7<lets keep it positive : ) x1=4 y1=5 \[\huge~\rm~y5=\frac{ 6 }{ 7 }(x4)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i suck at this stuff!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thats all it is buddy! :) You are doing just fine

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is that the answer? its not one of my choices

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0What are the choices?

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1I can finish up :) looks like they left

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0y+1=6/5(x+3) y+1=6/7(x+3) y1=6/7(x3) y+3=7/6(x+1)

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1oh ok the only problem is that they used the wrong point not hard to fix we always need to use the 2nd point so (3,1) and we get y+1=6/7(x+3) We get "+" because a negative and a negative touching each other make a postive :) understood?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i do! thank you! could you help me with a few more?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0linear inequality graph Which is an equation of the given line in standard form? A. –11x + 6y = –13 B. –6x +11y = 13 C. –6x + 11y = –13 D. –6x + 7y = –17

pooja195
 one year ago
Best ResponseYou've already chosen the best response.1wow i suck at standered for @Jaynator495

Jaynator495
 one year ago
Best ResponseYou've already chosen the best response.0Cannot help because you are from k12, sorry about this... you can ask indirect questions but NO test questions...
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