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anonymous

  • one year ago

Which is an equation in point-slope form of the line that passes through the points (4,5) and (-3, -1)

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  1. anonymous
    • one year ago
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    We need to find the slope first so \[\frac{ y_2-y_1 }{ x_2-x_1 }\]

  2. anonymous
    • one year ago
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    Can you find the slope using that formula please? ^_^

  3. anonymous
    • one year ago
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    \[11\frac{ ? }{ ? }-8\]

  4. anonymous
    • one year ago
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    oops sorry! 11 over -8

  5. anonymous
    • one year ago
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    Not quite I will set up the problem for you :) \[\huge~\rm~\frac{ -1-5 }{ -3-4 }=slope\]

  6. anonymous
    • one year ago
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    -6 over -7?

  7. anonymous
    • one year ago
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    yes :) Alright next step is to pick a point lets got with (4,5) Are you fimilar with this formula? \[\huge~\rm~y-y_1=m(x-x_1)\]

  8. anonymous
    • one year ago
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    not really

  9. anonymous
    • one year ago
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    \[\huge~\rm~y-y_1=m(x-x_1)\] M=slope=6/7<--lets keep it positive : ) x1=4 y1=5 Can you sub in the values please? :)

  10. anonymous
    • one year ago
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    5-5=6/7(4-4)

  11. anonymous
    • one year ago
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    No quite we do not need to plug in the values for the varibles that have no number \[\huge~\rm~y-y_1=m(x-x_1)\] M=slope=6/7<--lets keep it positive : ) x1=4 y1=5 \[\huge~\rm~y-5=\frac{ 6 }{ 7 }(x-4)\]

  12. anonymous
    • one year ago
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    i suck at this stuff!

  13. anonymous
    • one year ago
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    Thats all it is buddy! :) You are doing just fine

  14. anonymous
    • one year ago
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    is that the answer? its not one of my choices

  15. anonymous
    • one year ago
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    What are the choices?

  16. anonymous
    • one year ago
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    Hello?

  17. anonymous
    • one year ago
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    in here! sorry!

  18. pooja195
    • one year ago
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    I can finish up :) looks like they left

  19. anonymous
    • one year ago
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    y+1=6/5(x+3) y+1=6/7(x+3) y-1=6/7(x-3) y+3=7/6(x+1)

  20. pooja195
    • one year ago
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    oh ok the only problem is that they used the wrong point not hard to fix we always need to use the 2nd point so (-3,-1) and we get y+1=6/7(x+3) We get "+" because a negative and a negative touching each other make a postive :) understood?

  21. anonymous
    • one year ago
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    i do! thank you! could you help me with a few more?

  22. anonymous
    • one year ago
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    linear inequality graph Which is an equation of the given line in standard form? A. –11x + 6y = –13 B. –6x +11y = 13 C. –6x + 11y = –13 D. –6x + 7y = –17

  23. pooja195
    • one year ago
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    wow i suck at standered for @Jaynator495

  24. Jaynator495
    • one year ago
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    Cannot help because you are from k12, sorry about this... you can ask indirect questions but NO test questions...

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