anonymous
  • anonymous
find m∠A.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
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anonymous
  • anonymous
plz help
taramgrant0543664
  • taramgrant0543664
You can use the formula a^2=c^2+b^2-2abcosA, just put your values in for a,b and c and solve for A

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anonymous
  • anonymous
can you help me plug them in ... im really confused :(
taramgrant0543664
  • taramgrant0543664
So a=4, b=5 and c=2
taramgrant0543664
  • taramgrant0543664
4^2=(5^2)+(2^2)-2(5)(2)cosA I realized in the second portion it should have been bc not ab
taramgrant0543664
  • taramgrant0543664
16=25+4-20cosA 16=29-20cosA -13=-20cosA 0.65=cosA A=? Are you able to finish that?
anonymous
  • anonymous
would divide 0.64 by cosA? if it is right im not really sure how to solve it
taramgrant0543664
  • taramgrant0543664
Nope you have to do the inverse of the cosine function in order to get A by itself so: \[\cos ^{-1}(0.65)\]
anonymous
  • anonymous
ohh... i know im gonna sound kinda dumb.. but how do you do the inverse?
anonymous
  • anonymous
i dont mean to sound mean but can you give me the answer i only have couple of mins left ! im on a timed quiz
taramgrant0543664
  • taramgrant0543664
It's 49.46
anonymous
  • anonymous
thank you so much taramgrant ! really appreciate it :) :)
taramgrant0543664
  • taramgrant0543664
No problem!

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