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anonymous

  • one year ago

find m∠A.

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  1. anonymous
    • one year ago
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  2. anonymous
    • one year ago
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    plz help

  3. taramgrant0543664
    • one year ago
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    You can use the formula a^2=c^2+b^2-2abcosA, just put your values in for a,b and c and solve for A

  4. anonymous
    • one year ago
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    can you help me plug them in ... im really confused :(

  5. taramgrant0543664
    • one year ago
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    So a=4, b=5 and c=2

  6. taramgrant0543664
    • one year ago
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    4^2=(5^2)+(2^2)-2(5)(2)cosA I realized in the second portion it should have been bc not ab

  7. taramgrant0543664
    • one year ago
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    16=25+4-20cosA 16=29-20cosA -13=-20cosA 0.65=cosA A=? Are you able to finish that?

  8. anonymous
    • one year ago
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    would divide 0.64 by cosA? if it is right im not really sure how to solve it

  9. taramgrant0543664
    • one year ago
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    Nope you have to do the inverse of the cosine function in order to get A by itself so: \[\cos ^{-1}(0.65)\]

  10. anonymous
    • one year ago
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    ohh... i know im gonna sound kinda dumb.. but how do you do the inverse?

  11. anonymous
    • one year ago
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    i dont mean to sound mean but can you give me the answer i only have couple of mins left ! im on a timed quiz

  12. taramgrant0543664
    • one year ago
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    It's 49.46

  13. anonymous
    • one year ago
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    thank you so much taramgrant ! really appreciate it :) :)

  14. taramgrant0543664
    • one year ago
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    No problem!

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spraguer (Moderator)
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