superhelp101
  • superhelp101
Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 8.4 moles of lithium hydroxide? (1 point) LiOH + H2SO4 yields Li2SO4 + H2O 2.1 moles 4.2 moles 8.4 moles 16.8 moles
Chemistry
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superhelp101
  • superhelp101
Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 8.4 moles of lithium hydroxide? (1 point) LiOH + H2SO4 yields Li2SO4 + H2O 2.1 moles 4.2 moles 8.4 moles 16.8 moles
Chemistry
jamiebookeater
  • jamiebookeater
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superhelp101
  • superhelp101
abb0t
  • abb0t
Yes?
superhelp101
  • superhelp101
can you help me on this question please :)

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taramgrant0543664
  • taramgrant0543664
Your first step is to balance do you know how to do that?
superhelp101
  • superhelp101
no
superhelp101
  • superhelp101
2 LiOH + H2SO4 = Li2SO4 + 2 H2O
taramgrant0543664
  • taramgrant0543664
Yep that is balanced
taramgrant0543664
  • taramgrant0543664
So now we have to determine how may moles of H2SO4 are needed to react with the 8.4mols of LiOH So the first step to realize is that for every one mole of H2SO4 is used, two moles of LiOH are used. So: 8.4mol LiOH * (1 mol H2SO4/2mol LiOH) * (98.08g/mol H2SO4/1mol H2SO4)= ? g H2SO4
superhelp101
  • superhelp101
I got 4.2 moles
taramgrant0543664
  • taramgrant0543664
Ya it would be 4.2 mol of H2SO4
superhelp101
  • superhelp101
yeas thanks for the help :) :D
taramgrant0543664
  • taramgrant0543664
No problem!

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