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superhelp101

  • one year ago

Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 8.4 moles of lithium hydroxide? (1 point) LiOH + H2SO4 yields Li2SO4 + H2O 2.1 moles 4.2 moles 8.4 moles 16.8 moles

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  1. superhelp101
    • one year ago
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    @abb0t

  2. abb0t
    • one year ago
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    Yes?

  3. superhelp101
    • one year ago
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    can you help me on this question please :)

  4. taramgrant0543664
    • one year ago
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    Your first step is to balance do you know how to do that?

  5. superhelp101
    • one year ago
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    no

  6. superhelp101
    • one year ago
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    2 LiOH + H2SO4 = Li2SO4 + 2 H2O

  7. taramgrant0543664
    • one year ago
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    Yep that is balanced

  8. taramgrant0543664
    • one year ago
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    So now we have to determine how may moles of H2SO4 are needed to react with the 8.4mols of LiOH So the first step to realize is that for every one mole of H2SO4 is used, two moles of LiOH are used. So: 8.4mol LiOH * (1 mol H2SO4/2mol LiOH) * (98.08g/mol H2SO4/1mol H2SO4)= ? g H2SO4

  9. superhelp101
    • one year ago
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    I got 4.2 moles

  10. taramgrant0543664
    • one year ago
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    Ya it would be 4.2 mol of H2SO4

  11. superhelp101
    • one year ago
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    yeas thanks for the help :) :D

  12. taramgrant0543664
    • one year ago
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    No problem!

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