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superhelp101
 one year ago
Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 8.4 moles of lithium hydroxide? (1 point)
LiOH + H2SO4 yields Li2SO4 + H2O
2.1 moles
4.2 moles
8.4 moles
16.8 moles
superhelp101
 one year ago
Upon balancing the equation below, how many moles of sulfuric acid are needed to react completely with 8.4 moles of lithium hydroxide? (1 point) LiOH + H2SO4 yields Li2SO4 + H2O 2.1 moles 4.2 moles 8.4 moles 16.8 moles

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superhelp101
 one year ago
Best ResponseYou've already chosen the best response.0can you help me on this question please :)

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Your first step is to balance do you know how to do that?

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.02 LiOH + H2SO4 = Li2SO4 + 2 H2O

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Yep that is balanced

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1So now we have to determine how may moles of H2SO4 are needed to react with the 8.4mols of LiOH So the first step to realize is that for every one mole of H2SO4 is used, two moles of LiOH are used. So: 8.4mol LiOH * (1 mol H2SO4/2mol LiOH) * (98.08g/mol H2SO4/1mol H2SO4)= ? g H2SO4

taramgrant0543664
 one year ago
Best ResponseYou've already chosen the best response.1Ya it would be 4.2 mol of H2SO4

superhelp101
 one year ago
Best ResponseYou've already chosen the best response.0yeas thanks for the help :) :D
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