superhelp101
  • superhelp101
Question:
Chemistry
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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superhelp101
  • superhelp101
How many grams of NaOH can be formed when 43.0 grams of Na2O react with 27.0 grams of H2O? (1 point) Na2O + H2O yields NaOH Be sure to balance the equation. 13.9 grams 18.0 grams 27.0 grams 55.5 grams How many grams of H2 are needed to react completely with 44.1 grams of C? (1 point) C + H2 yields CH4 Be sure to balance the equation. 7.40 grams 14.7 grams 88.2 grams 132 grams
superhelp101
  • superhelp101
@taramgrant0543664
taramgrant0543664
  • taramgrant0543664
So lets start with the first one and balance it, are you able to do that?

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superhelp101
  • superhelp101
yes Na2O + H2O = 2 NaOH
taramgrant0543664
  • taramgrant0543664
Perfect now we need to determine which of the reactants is the limiting reagent to do this we take the mass and divide by the solar mass: 43g Na2O * (1mol Na2O/61.98g/mol)=? 27g H2O * (1mol H2O/18.02g/mol)=?
superhelp101
  • superhelp101
um..having trouble with that part
taramgrant0543664
  • taramgrant0543664
Are you able to elaborate which part you are having problems with?
superhelp101
  • superhelp101
43g Na2O * (1mol Na2O/61.98g/mol)=? 27g H2O * (1mol H2O/18.02g/mol)=? :)
taramgrant0543664
  • taramgrant0543664
Ok so the first one there we will get 0.694mol of Na2O and 1.50mol of H20 so the limiting reagent will be the Na2O
taramgrant0543664
  • taramgrant0543664
Knowing that the Na2O is the limiting reagent we can use this to determine the yield of NaOH so: 0.694mol Na2O * (2mol NaOH/1mol Na2O) * (39.99g/mol /1mol NaOH) = ? g NaOH
superhelp101
  • superhelp101
I think i got18.0 grams
superhelp101
  • superhelp101
wait idk :/
taramgrant0543664
  • taramgrant0543664
Sorry I messed something up one sec
taramgrant0543664
  • taramgrant0543664
Wait no I was looking at the wrong options for a sec lol when I did the math I got the 55.5
superhelp101
  • superhelp101
ohhh okay I think i messed up with a number too :) but 55.5 i agree too
taramgrant0543664
  • taramgrant0543664
Awesome so lets do the second one, do you want to balance it?
superhelp101
  • superhelp101
C + 2 H2 = CH4
taramgrant0543664
  • taramgrant0543664
Perfect! So for this one we don't need to find the limiting reagent. We can start with: 44.1g C * (1mol C/ 12.01g/mol C) * (2mol H2/ 1molC) * (2.02g/mol H2/ 1mol H2)= ?gH2
superhelp101
  • superhelp101
7.40 grams?
taramgrant0543664
  • taramgrant0543664
You missed multiplying it by another two somewhere in there I believe
superhelp101
  • superhelp101
I might have multipled by the wrong thing..132 grams i believe
taramgrant0543664
  • taramgrant0543664
When I went through it I ended with 14.8 since I carried all decimals without decimal carrying I got 14.7
superhelp101
  • superhelp101
lol i'm sorry i made a simple error hahah :)
taramgrant0543664
  • taramgrant0543664
That is no problem lol happens to everyone!
superhelp101
  • superhelp101
:D

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