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anonymous

  • one year ago

Find an equation for the nth term of the arithmetic sequence. a19 = -92, a20 = 6 an = -1856 + 98(n - 1) an = -1856 - 98(n - 1) an = -1856 - 98(n + 1) an = -1856 + 98(n + 1) @dan815 @jim_thompson5910 @mathstudent55 @compassionate @zzr0ck3r

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  1. jim_thompson5910
    • one year ago
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    First isolate d \[\Large a_{19} + d = a_{20}\] \[\Large -92 + d = 6\] \[\Large d= ???\]

  2. anonymous
    • one year ago
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    -86 @jim_thompson5910

  3. anonymous
    • one year ago
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    then what do we do? @jim_thompson5910

  4. jim_thompson5910
    • one year ago
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    you add 92 to both sides

  5. jim_thompson5910
    • one year ago
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    6+92 = ??

  6. anonymous
    • one year ago
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    98 @jim_thompson5910

  7. jim_thompson5910
    • one year ago
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    so d = 98

  8. jim_thompson5910
    • one year ago
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    which is why the answer is |dw:1436316159029:dw|

  9. jim_thompson5910
    • one year ago
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    |dw:1436316211464:dw|

  10. jim_thompson5910
    • one year ago
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    first term is \[\Large a_1 = -1856\] |dw:1436316259108:dw|

  11. jim_thompson5910
    • one year ago
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    common difference is d = 98 we add 98 to each term to get the next term |dw:1436316282925:dw|

  12. anonymous
    • one year ago
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    so a is the final answer? @jim_thompson5910

  13. jim_thompson5910
    • one year ago
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    yeah

  14. jim_thompson5910
    • one year ago
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    |dw:1436316316037:dw|

  15. anonymous
    • one year ago
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    can u help me with another one? @jim_thompson5910

  16. jim_thompson5910
    • one year ago
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    sure

  17. anonymous
    • one year ago
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    Find an equation for the nth term of the arithmetic sequence. -17, -13, -9, -5, ... an = -17 + 4(n + 2) an = -17 x 4(n - 1) an = -17 + 4(n - 1) an = -17 + 4(n + 1)

  18. jim_thompson5910
    • one year ago
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    what's the first term?

  19. anonymous
    • one year ago
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    i dont know @jim_thompson5910

  20. jim_thompson5910
    • one year ago
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    just look at the first number given in the sequence

  21. anonymous
    • one year ago
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    -17 @jim_thompson5910

  22. jim_thompson5910
    • one year ago
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    yeah

  23. jim_thompson5910
    • one year ago
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    what must we add to -17 to get to the next term -13 ?

  24. anonymous
    • one year ago
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    4 @jim_thompson5910

  25. jim_thompson5910
    • one year ago
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    so d = 4

  26. jim_thompson5910
    • one year ago
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    First term \[\Large a_1 = -17\] Common difference \[\Large d = 4\]

  27. jim_thompson5910
    • one year ago
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    |dw:1436316606279:dw|

  28. anonymous
    • one year ago
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    so the answer would be c? @jim_thompson5910

  29. jim_thompson5910
    • one year ago
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    |dw:1436316636005:dw|

  30. jim_thompson5910
    • one year ago
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    |dw:1436316659391:dw|

  31. jim_thompson5910
    • one year ago
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    yes, c

  32. anonymous
    • one year ago
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    Find an equation for the nth term of a geometric sequence where the second and fifth terms are -2 and 16, respectively. an = 1 • (-2)n - 1 an = 1 • 2n an = 1 • (-2)n + 1 an = 1 • 2n - 1 @jim_thompson5910 one more?

  33. jim_thompson5910
    • one year ago
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    show me what you have so far

  34. anonymous
    • one year ago
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    i dont have anything? i dont know how to do it?

  35. anonymous
    • one year ago
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    @jim_thompson5910

  36. jim_thompson5910
    • one year ago
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    second term = -2 third term = -2*r = -2r fourth term = (-2r)*r = -2r^2 fifth term = (-2r^2)*r = -2r^3 ------------------------------------------------------- solve for r -2r^3 = 16

  37. anonymous
    • one year ago
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    how do i do thta? @jim_thompson5910

  38. jim_thompson5910
    • one year ago
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    you need to isolate r try to get r all by itself

  39. jim_thompson5910
    • one year ago
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    think to yourself -2 times _________ = 16 what goes in the blank?

  40. anonymous
    • one year ago
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    r

  41. jim_thompson5910
    • one year ago
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    -2 times _________ = 16 think of a number that goes in the blank

  42. anonymous
    • one year ago
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    i got 1.25

  43. anonymous
    • one year ago
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    @jim_thompson5910

  44. jim_thompson5910
    • one year ago
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    no

  45. anonymous
    • one year ago
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    so what is it?

  46. jim_thompson5910
    • one year ago
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    this article may help http://www.purplemath.com/modules/solvelin.htm

  47. jim_thompson5910
    • one year ago
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    it shows how to solve equations

  48. anonymous
    • one year ago
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    i dont know? im stupid lol @jim_thompson5910

  49. jim_thompson5910
    • one year ago
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    read that article a few times. It should help you aren't stupid

  50. anonymous
    • one year ago
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    can u show me step by step im more of a visual person @jim_thompson5910

  51. jim_thompson5910
    • one year ago
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    for example 2 times x = 10 means x = 5 since 2 times 5 = 10

  52. jim_thompson5910
    • one year ago
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    2q = 28 means q = 14 because 2 times 14 = 28

  53. jim_thompson5910
    • one year ago
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    you can divide both sides by 2 to isolate the variable

  54. anonymous
    • one year ago
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    so then its r^3=-8 @jim_thompson5910

  55. jim_thompson5910
    • one year ago
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    very good

  56. jim_thompson5910
    • one year ago
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    to undo the cube exponent, we take the cube root of both sides |dw:1436317751492:dw|

  57. jim_thompson5910
    • one year ago
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    |dw:1436317761724:dw|

  58. anonymous
    • one year ago
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    i got this 1±i√3

  59. jim_thompson5910
    • one year ago
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    |dw:1436317773660:dw|

  60. jim_thompson5910
    • one year ago
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    only focus on the real solutions

  61. jim_thompson5910
    • one year ago
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    |dw:1436317819217:dw|

  62. anonymous
    • one year ago
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    so the answer is a?

  63. jim_thompson5910
    • one year ago
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    |dw:1436317839091:dw|

  64. jim_thompson5910
    • one year ago
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    yeah it's the only one that fits

  65. jim_thompson5910
    • one year ago
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    so a1 has to be 1

  66. anonymous
    • one year ago
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    one last one? @jim_thompson5910

  67. anonymous
    • one year ago
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    Write the sum using summation notation, assuming the suggested pattern continues. -1 + 2 + 5 + 8 + ... + 44 summation of negative three times n from n equals zero to fifteen summation of the quantity negative one plus three n from n equals zero to fifteen summation of negative three times n from n equals zero to infinity summation of the quantity negative one plus three n from n equals zero to infinity

  68. anonymous
    • one year ago
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    @jim_thompson5910 @UsukiDoll

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