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anonymous
 one year ago
Find an equation for the nth term of the arithmetic sequence.
a19 = 92, a20 = 6
an = 1856 + 98(n  1)
an = 1856  98(n  1)
an = 1856  98(n + 1)
an = 1856 + 98(n + 1)
@dan815 @jim_thompson5910 @mathstudent55 @compassionate @zzr0ck3r
anonymous
 one year ago
Find an equation for the nth term of the arithmetic sequence. a19 = 92, a20 = 6 an = 1856 + 98(n  1) an = 1856  98(n  1) an = 1856  98(n + 1) an = 1856 + 98(n + 1) @dan815 @jim_thompson5910 @mathstudent55 @compassionate @zzr0ck3r

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jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0First isolate d \[\Large a_{19} + d = a_{20}\] \[\Large 92 + d = 6\] \[\Large d= ???\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.086 @jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0then what do we do? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0you add 92 to both sides

anonymous
 one year ago
Best ResponseYou've already chosen the best response.098 @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0which is why the answer is dw:1436316159029:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436316211464:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0first term is \[\Large a_1 = 1856\] dw:1436316259108:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0common difference is d = 98 we add 98 to each term to get the next term dw:1436316282925:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so a is the final answer? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436316316037:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u help me with another one? @jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find an equation for the nth term of the arithmetic sequence. 17, 13, 9, 5, ... an = 17 + 4(n + 2) an = 17 x 4(n  1) an = 17 + 4(n  1) an = 17 + 4(n + 1)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what's the first term?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0just look at the first number given in the sequence

anonymous
 one year ago
Best ResponseYou've already chosen the best response.017 @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0what must we add to 17 to get to the next term 13 ?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0First term \[\Large a_1 = 17\] Common difference \[\Large d = 4\]

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436316606279:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so the answer would be c? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436316636005:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436316659391:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Find an equation for the nth term of a geometric sequence where the second and fifth terms are 2 and 16, respectively. an = 1 • (2)n  1 an = 1 • 2n an = 1 • (2)n + 1 an = 1 • 2n  1 @jim_thompson5910 one more?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0show me what you have so far

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont have anything? i dont know how to do it?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0second term = 2 third term = 2*r = 2r fourth term = (2r)*r = 2r^2 fifth term = (2r^2)*r = 2r^3  solve for r 2r^3 = 16

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how do i do thta? @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0you need to isolate r try to get r all by itself

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0think to yourself 2 times _________ = 16 what goes in the blank?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.02 times _________ = 16 think of a number that goes in the blank

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0this article may help http://www.purplemath.com/modules/solvelin.htm

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0it shows how to solve equations

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i dont know? im stupid lol @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0read that article a few times. It should help you aren't stupid

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u show me step by step im more of a visual person @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0for example 2 times x = 10 means x = 5 since 2 times 5 = 10

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.02q = 28 means q = 14 because 2 times 14 = 28

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0you can divide both sides by 2 to isolate the variable

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so then its r^3=8 @jim_thompson5910

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0to undo the cube exponent, we take the cube root of both sides dw:1436317751492:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436317761724:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436317773660:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0only focus on the real solutions

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436317819217:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436317839091:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0yeah it's the only one that fits

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.0so a1 has to be 1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0one last one? @jim_thompson5910

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Write the sum using summation notation, assuming the suggested pattern continues. 1 + 2 + 5 + 8 + ... + 44 summation of negative three times n from n equals zero to fifteen summation of the quantity negative one plus three n from n equals zero to fifteen summation of negative three times n from n equals zero to infinity summation of the quantity negative one plus three n from n equals zero to infinity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 @UsukiDoll
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