anonymous
  • anonymous
Find the vertex, focus, directrix, and focal width of the parabola. -(1/16)x^2 = y
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
OMG I was just working on this with my friend!!! Okay, so do you have any ideas how to solve this problem?
anonymous
  • anonymous
Not really.
anonymous
  • anonymous
Okay.... Well, do you know any definitions?

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anonymous
  • anonymous
I think I know the right answer. I just have an odd way of solving it, and I wanted someone to verify it. I got; vertex (0,0); focus (0,-4) directrix y=4; focal width=16
anonymous
  • anonymous
Yes! That is correct! How do you solve it?
anonymous
  • anonymous
I have an odd manner and it's complicated to explain, most of it I do in my head.
anonymous
  • anonymous
Thanks for the help
anonymous
  • anonymous
Ah. Okay. I'm all for weirdo methods! Always do those kinds of things at my school! I solve it by plotting the vertex, moving down the P (see formula), and moving up the p for the directrix, and then if the parabola is up and down, the line is horizontal, and vice versa! No problem! I LOVE this topic, so let me know if you have anymore questions with conics!

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