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ASAPT
 one year ago
Find the value of x and the value of y.
ASAPT
 one year ago
Find the value of x and the value of y.

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ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0im not sure im pretty bad at geometry

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0ok do you know the answer?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can't use the law of cosines unless you know the angle opposite the side you're looking for.

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0oh ok do you know the answer?

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0ugh why is this so difficult

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Look at the lengths of CB and BA. What is their sum?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Compare this sum to 48. How is this possible?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0There is only one explanation. Once you see this, the answer will POP.

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Actually, just look at the lengths of CE and BA.

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0Sum them and compare to 48. What MUST x be in this case?

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0You know that the lengths of 2 sides of a triangle MUST be greater than the third side, right?

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0so what would that mean my answer is @ybarrap

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0forget about that approach

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0this can't be right, forget that approach too. The reason is that y could be anything and that doesn't make sense.

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0no it was I submitted it and it said it was right

ASAPT
 one year ago
Best ResponseYou've already chosen the best response.0I have more to do if you want to help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436331441040:dw

ybarrap
 one year ago
Best ResponseYou've already chosen the best response.0I just realized angle D and angle B are equal :( @surjithayer used similarity  Nice job!

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0You are dealing with two similar triangles. Since <B =~ <CDE and <C =~ <C, by ASA Similarity, triangles ABC and EDC are similar. That makes the lengths of corresponding sides proportional. The easiest way to see this is to redraw the figure with the triangles separated and turned in the same direction so you can see the similarity. Se figure below. dw:1436329185777:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.0Now we see how the triangles are similar. Since x is part of side BC, we need the length of side BC. From similarity, we get this proportion: \(\dfrac{CE}{CA} = \dfrac{CD}{BC} \) \(\dfrac{24}{48} = \dfrac{18}{BC} \) \(\dfrac{1}{2} = \dfrac{18}{BC} \) \(BC = 36\) Since \(BC = 36\), and \(CE = 24\), then \(x = BE = 36  24 = 12\) Now we need y. \(\dfrac{CE}{CA} = \dfrac{DE}{BA} \) \(\dfrac{24}{48} = \dfrac{y}{24} \) \(\dfrac{1}{2} = \dfrac{y}{24} \) \(y = 12\)
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