anonymous
  • anonymous
Write the sum using summation notation, assuming the suggested pattern continues. -1 + 2 + 5 + 8 + ... + 44 summation of negative three times n from n equals zero to fifteen summation of the quantity negative one plus three n from n equals zero to fifteen summation of negative three times n from n equals zero to infinity summation of the quantity negative one plus three n from n equals zero to infinity @dan815 @solomonzelman @mathstudent55 @luigi0210 @sammixboo
Mathematics
katieb
  • katieb
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

Haseeb96
  • Haseeb96
|dw:1436318296947:dw|
anonymous
  • anonymous
okay so what do we do next @ha
anonymous
  • anonymous

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

misty1212
  • misty1212
HI!!
misty1212
  • misty1212
they are asking for sigma notation, not a formula for the sum, right?
anonymous
  • anonymous
Haseeb96
  • Haseeb96
okay okay @misty1212 you should help her I dont know how to solve summatation question and tell us in easy way how to find out the summation
misty1212
  • misty1212
\[\sum_{n=-1}^{?}-1+3n\] looks good now we need the upper limit
misty1212
  • misty1212
oops that is wrong, i meant \[\sum_{n=0}^{?}-1+3n\] because you are adding 3 each time
Haseeb96
  • Haseeb96
how did you take out this expression (-1+3n) ? @misty1212
anonymous
  • anonymous
i think it would be infinity on top
misty1212
  • misty1212
to figure out the upper limit, set \[1+3n=44\] solve for \(n\) you should get \(n=15\) making your answer \[\huge\sum_{n=0}^{15}-1+3n\]
misty1212
  • misty1212
ok it does say "assuming the pattern continues" so maybe they want \[\sum_{n=0]^{\infty}--+3n\]
misty1212
  • misty1212
dang \[\sum_{n=0}^{\infty}-1+3n\]
misty1212
  • misty1212
which is kind of silly since that is not a number, but whatever
anonymous
  • anonymous
thank you so much @misty1212

Looking for something else?

Not the answer you are looking for? Search for more explanations.