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anonymous
 one year ago
Write the sum using summation notation, assuming the suggested pattern continues.
1 + 2 + 5 + 8 + ... + 44
summation of negative three times n from n equals zero to fifteen
summation of the quantity negative one plus three n from n equals zero to fifteen
summation of negative three times n from n equals zero to infinity
summation of the quantity negative one plus three n from n equals zero to infinity
@dan815 @solomonzelman @mathstudent55 @luigi0210 @sammixboo
anonymous
 one year ago
Write the sum using summation notation, assuming the suggested pattern continues. 1 + 2 + 5 + 8 + ... + 44 summation of negative three times n from n equals zero to fifteen summation of the quantity negative one plus three n from n equals zero to fifteen summation of negative three times n from n equals zero to infinity summation of the quantity negative one plus three n from n equals zero to infinity @dan815 @solomonzelman @mathstudent55 @luigi0210 @sammixboo

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Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.0dw:1436318296947:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so what do we do next @ha

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0they are asking for sigma notation, not a formula for the sum, right?

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.0okay okay @misty1212 you should help her I dont know how to solve summatation question and tell us in easy way how to find out the summation

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0\[\sum_{n=1}^{?}1+3n\] looks good now we need the upper limit

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0oops that is wrong, i meant \[\sum_{n=0}^{?}1+3n\] because you are adding 3 each time

Haseeb96
 one year ago
Best ResponseYou've already chosen the best response.0how did you take out this expression (1+3n) ? @misty1212

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think it would be infinity on top

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0to figure out the upper limit, set \[1+3n=44\] solve for \(n\) you should get \(n=15\) making your answer \[\huge\sum_{n=0}^{15}1+3n\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0ok it does say "assuming the pattern continues" so maybe they want \[\sum_{n=0]^{\infty}+3n\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0dang \[\sum_{n=0}^{\infty}1+3n\]

misty1212
 one year ago
Best ResponseYou've already chosen the best response.0which is kind of silly since that is not a number, but whatever

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much @misty1212
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