A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 one year ago
13 peas are generated from parents having the green and yellow pair of genes, so there is 0.75 probability that an individual will have a green pod. Find the probability that the 13 offspring peas, at least 12 have green pods. Is it unusual to get 12 peas with green pods when 13 offsprings are generated
anonymous
 one year ago
13 peas are generated from parents having the green and yellow pair of genes, so there is 0.75 probability that an individual will have a green pod. Find the probability that the 13 offspring peas, at least 12 have green pods. Is it unusual to get 12 peas with green pods when 13 offsprings are generated

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how many ways can 12 of the 13 peas be selected (i.e. be green)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\(\binom{13}{12}=\binom{13}1=13\) such ways. now compute the probability of any particular such way: 12 peas green is \(0.75^{12}\) while the one pea notgreen is \((10.75)^1=0.25\) so our total probability is: $$13\cdot0.75^{12}\cdot0.25\approx 0.1029$$

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so there's a ~10.3% chance this occurs randomly  it's not super common, but not particularly unusual

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops, you said at *least* 12 pods, so there is also the chance all thirteen are green

kropot72
 one year ago
Best ResponseYou've already chosen the best response.0To get the answer to the question it is necessary to add the probability that all 13 will be green. Therefore we need to find: \[\large (at\ least\ 12\ green)=0.1029+(0.75)^{13}=you\ can\ calculate\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in which case there's \(\binom{13}{13}=1\) such possible ways they can all turn green and the probability is \(0.75^{13}\approx 0.0238\) so our total probability is \(\text{probability 12 are green}+\text{probability all are green}\approx0.1029+0.0238=0.1267\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.