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YumYum247
 one year ago
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YumYum247
 one year ago
5

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so in 0.10 seconds the wave generator goes through 3 cycles; the frequency is \(f=\frac{N}{\Delta t}=30\text{ Hz}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in one single second, there will be ten times as many waves produced (30)

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0This is how i did it... Given: # of loops = 3, d = 4.5m, t = 0.10sec. required: F = ? Solution : 3 loops = 3/4 λ = 3/4 λ X 3 = 4.5 λ V = d/t V = 4.5 / 0.10sec V = 45m/sec Frequency = V = f X λ V = 45m/sec / 4.5 λ V = 10 Hz Therefore the frequency is 10 Hz

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0the question said "LOOPS" not cycles

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.01 complete cycle = 4 loops

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0eh, the language is ambiguous; a complete loop would be half a cycle, anyways, so in actuality that would represent oneandahalf cycles in 0.1 seconds and so a corresponding 15 cycles in 1 second, or \(f=15\text{ Hz}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can you define carefully what you mean by 'loop'? dw:1436322714361:dw

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0and what happened to the distance....4.5m?????????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the distance is not needed to determine the frequency here since you told us that it generates three loops in a certain time span directly

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i don't buy it, but thanks for the help tho.......:")

perl
 one year ago
Best ResponseYou've already chosen the best response.1you want to use that equation directly speed = wavelength * frequency

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0but i have to figure out the wavelength first right..............i've already done the question above. please check y work.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0Can someone please check my work?????????????????????????????????????????????????????

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm thinking that a loop is a full period. Though I'm just going from unit circle imagery :) dw:1436323530849:dw

perl
 one year ago
Best ResponseYou've already chosen the best response.1I agree, a complete loop sounds like 1 up and down motion.

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0OMg.....1 loop is 1/4 of a full cycle...heredw:1436334439572:dw

perl
 one year ago
Best ResponseYou've already chosen the best response.1v = lambda * f v= 45 m/sec lambda= (4.5 / 3) = 1.5 m 45 = (1.5) * f 45/1.5= 30 Hz

perl
 one year ago
Best ResponseYou've already chosen the best response.1Does your book define a loop?

perl
 one year ago
Best ResponseYou've already chosen the best response.1the youtube is defining 1 loop = 1/2 wavelength

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0oh that's right, sorry i made a mistake, i just looked at my notes LOL

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0i guess i'll jst re do the whole qeston...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0huh, I've never seen "loop" notation before.. best of luck

perl
 one year ago
Best ResponseYou've already chosen the best response.1but the term 'complete loop' seems to be suggestive

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0no but i plugged in the right value there....since there are three loops = 3/4Lambda

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for anyone else curious about "loops", refer to http://www.physicsclassroom.com/class/waves/Lesson4/MathematicsofStandingWaves Its only really used when describing standing waves such as this, as the string itself alternates between the upper and lower position between two antinodes

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.0@dan815 hey please check my work at the top!!!
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