5

At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions.

A community for students.

See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this and thousands of other questions

so in 0.10 seconds the wave generator goes through 3 cycles; the frequency is \(f=\frac{N}{\Delta t}=30\text{ Hz}\)
in one single second, there will be ten times as many waves produced (30)
This is how i did it... Given: # of loops = 3, d = 4.5m, t = 0.10sec. required: F = ? Solution : 3 loops = 3/4 λ = 3/4 λ X 3 = 4.5 λ V = d/t V = 4.5 / 0.10sec V = 45m/sec Frequency = V = f X λ V = 45m/sec / 4.5 λ V = 10 Hz Therefore the frequency is 10 Hz

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

the question said "LOOPS" not cycles
1 complete cycle = 4 loops
eh, the language is ambiguous; a complete loop would be half a cycle, anyways, so in actuality that would represent one-and-a-half cycles in 0.1 seconds and so a corresponding 15 cycles in 1 second, or \(f=15\text{ Hz}\)
can you define carefully what you mean by 'loop'? |dw:1436322714361:dw|
and what happened to the distance....4.5m?????????
the distance is not needed to determine the frequency here since you told us that it generates three loops in a certain time span directly
i don't buy it, but thanks for the help tho.......:")
you want to use that equation directly speed = wavelength * frequency
but i have to figure out the wavelength first right..............i've already done the question above. please check y work.
Can someone please check my work?????????????????????????????????????????????????????
I'm thinking that a loop is a full period. Though I'm just going from unit circle imagery :) |dw:1436323530849:dw|
I agree, a complete loop sounds like 1 up and down motion.
OMg.....1 loop is 1/4 of a full cycle...here|dw:1436334439572:dw|
v = lambda * f v= 45 m/sec lambda= (4.5 / 3) = 1.5 m 45 = (1.5) * f 45/1.5= 30 Hz
Does your book define a loop?
https://www.youtube.com/watch?v=1pZqlHgHzxI
start at 9:21
the youtube is defining 1 loop = 1/2 wavelength
oh that's right, sorry i made a mistake, i just looked at my notes LOL
OMG O_O!
i guess i'll jst re do the whole qeston...
huh, I've never seen "loop" notation before.. best of luck
but the term 'complete loop' seems to be suggestive
no but i plugged in the right value there....since there are three loops = 3/4Lambda
or 2/2 + 1/2lambda
for anyone else curious about "loops", refer to http://www.physicsclassroom.com/class/waves/Lesson-4/Mathematics-of-Standing-Waves Its only really used when describing standing waves such as this, as the string itself alternates between the upper and lower position between two antinodes
indeed
@dan815 hey please check my work at the top!!!

Not the answer you are looking for?

Search for more explanations.

Ask your own question