YumYum247
  • YumYum247
5
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
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anonymous
  • anonymous
so in 0.10 seconds the wave generator goes through 3 cycles; the frequency is \(f=\frac{N}{\Delta t}=30\text{ Hz}\)
anonymous
  • anonymous
in one single second, there will be ten times as many waves produced (30)
YumYum247
  • YumYum247
This is how i did it... Given: # of loops = 3, d = 4.5m, t = 0.10sec. required: F = ? Solution : 3 loops = 3/4 λ = 3/4 λ X 3 = 4.5 λ V = d/t V = 4.5 / 0.10sec V = 45m/sec Frequency = V = f X λ V = 45m/sec / 4.5 λ V = 10 Hz Therefore the frequency is 10 Hz

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YumYum247
  • YumYum247
the question said "LOOPS" not cycles
YumYum247
  • YumYum247
1 complete cycle = 4 loops
anonymous
  • anonymous
eh, the language is ambiguous; a complete loop would be half a cycle, anyways, so in actuality that would represent one-and-a-half cycles in 0.1 seconds and so a corresponding 15 cycles in 1 second, or \(f=15\text{ Hz}\)
anonymous
  • anonymous
can you define carefully what you mean by 'loop'? |dw:1436322714361:dw|
YumYum247
  • YumYum247
and what happened to the distance....4.5m?????????
anonymous
  • anonymous
the distance is not needed to determine the frequency here since you told us that it generates three loops in a certain time span directly
YumYum247
  • YumYum247
i don't buy it, but thanks for the help tho.......:")
perl
  • perl
you want to use that equation directly speed = wavelength * frequency
YumYum247
  • YumYum247
but i have to figure out the wavelength first right..............i've already done the question above. please check y work.
YumYum247
  • YumYum247
Can someone please check my work?????????????????????????????????????????????????????
anonymous
  • anonymous
I'm thinking that a loop is a full period. Though I'm just going from unit circle imagery :) |dw:1436323530849:dw|
perl
  • perl
I agree, a complete loop sounds like 1 up and down motion.
YumYum247
  • YumYum247
OMg.....1 loop is 1/4 of a full cycle...here|dw:1436334439572:dw|
perl
  • perl
v = lambda * f v= 45 m/sec lambda= (4.5 / 3) = 1.5 m 45 = (1.5) * f 45/1.5= 30 Hz
perl
  • perl
Does your book define a loop?
YumYum247
  • YumYum247
https://www.youtube.com/watch?v=1pZqlHgHzxI
YumYum247
  • YumYum247
start at 9:21
perl
  • perl
the youtube is defining 1 loop = 1/2 wavelength
YumYum247
  • YumYum247
oh that's right, sorry i made a mistake, i just looked at my notes LOL
YumYum247
  • YumYum247
OMG O_O!
YumYum247
  • YumYum247
i guess i'll jst re do the whole qeston...
anonymous
  • anonymous
huh, I've never seen "loop" notation before.. best of luck
perl
  • perl
but the term 'complete loop' seems to be suggestive
YumYum247
  • YumYum247
no but i plugged in the right value there....since there are three loops = 3/4Lambda
YumYum247
  • YumYum247
or 2/2 + 1/2lambda
anonymous
  • anonymous
for anyone else curious about "loops", refer to http://www.physicsclassroom.com/class/waves/Lesson-4/Mathematics-of-Standing-Waves Its only really used when describing standing waves such as this, as the string itself alternates between the upper and lower position between two antinodes
YumYum247
  • YumYum247
indeed
YumYum247
  • YumYum247
@dan815 hey please check my work at the top!!!

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