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YumYum247
 one year ago
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YumYum247
 one year ago
3

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YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1This is how i did it..... Given: 320Hz, N = 14, t = 7sec Solution: F = N/t = 14times/7sec = 2Hz Fb = f1 + f2 fb = 320Hz + 2 Hz fb = 322Hz or fb = 318Hz

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1either could be true in this case!!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1am i right?????????????o_O

Astrophysics
 one year ago
Best ResponseYou've already chosen the best response.1This is like the problem we did yesterday, \[\huge f_{beats} = f_2f_1\] \[\large f_{beats} = \frac{ 14 }{ 7 } = 2 Hz\]\[2Hz = f_2  320 Hz \implies \pm 2 Hz = f_2320HZ\] so yes! You're good!

YumYum247
 one year ago
Best ResponseYou've already chosen the best response.1actually that problem is coming right now...right after this question!!! LOL
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