vshiroky
  • vshiroky
Need answer verification please (2y)^2+4y When y=-3 We got 24
Mathematics
  • Stacey Warren - Expert brainly.com
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jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
UsukiDoll
  • UsukiDoll
when y = -3 we have \[(2(-3))^2+4(-3)\] \[(-6)^2 -12 \] \[36-12 = 24\]
vshiroky
  • vshiroky
Could you check another?
UsukiDoll
  • UsukiDoll
sure

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More answers

vshiroky
  • vshiroky
Thank you, I'm trying to help her finish hers so I can start on mine lol
vshiroky
  • vshiroky
m^3+3(x+2) when m=-2 and x=4
vshiroky
  • vshiroky
I got 10, she got 14
UsukiDoll
  • UsukiDoll
ok so first we need to plug in m=-2 and x = 4 \[m^3+3(x+2) \] \[(-2)^3+3(4+2)\] \[\[-8+3(6)\]\] \[-8+18 = 10 \]
vshiroky
  • vshiroky
Do you care if I keep typing more?
UsukiDoll
  • UsukiDoll
depends on the topic and difficulty how many more problems?
vshiroky
  • vshiroky
Same stuff and I will take whatever help you can give until you dont want to anymore because there is quite a few more
UsukiDoll
  • UsukiDoll
ok...
vshiroky
  • vshiroky
6k^3+3d k=-1 and d=-2 We got -12
UsukiDoll
  • UsukiDoll
\[6k^3+3d \] for k=-1 and d = -2 \[6(-1)^3+3(-2) \] \[6(-1)+3(-2) \rightarrow -6-6 =-12\]
vshiroky
  • vshiroky
Thanks... (4+x)^2/x-6 when x=6 We got 100
UsukiDoll
  • UsukiDoll
\[\frac{(4+x)^2}{x-6}\] for x = 6.. wait a minute... this is undefined... if we let x = 6 in the denominator we will have 100/0 and we can't have a 0 in the denominator.
vshiroky
  • vshiroky
oops it was supposed to be x-1 on the bottom
vshiroky
  • vshiroky
so 20 is the answer
UsukiDoll
  • UsukiDoll
oH! xxxxxxxxxxxxxxD
UsukiDoll
  • UsukiDoll
\[\frac{(4+x)^2}{x-1}\] for x = 6 100/5 = 20 yup !
vshiroky
  • vshiroky
The next one is 4+7/x-2 + 3 when x=5 We got 6 2/3
UsukiDoll
  • UsukiDoll
is it \[4 + \frac{7}{x}-2 +3\] or \[4 + \frac{7}{x-2} +3\] ???
UsukiDoll
  • UsukiDoll
I don't understand the format of the question... could you draw it out?
vshiroky
  • vshiroky
Ill just skip that one I cant figure out how to type it lol
vshiroky
  • vshiroky
I'll try
vshiroky
  • vshiroky
|dw:1436328059205:dw|
UsukiDoll
  • UsukiDoll
that's better.
UsukiDoll
  • UsukiDoll
|dw:1436328132055:dw|
UsukiDoll
  • UsukiDoll
|dw:1436328175777:dw|
vshiroky
  • vshiroky
WOOO
vshiroky
  • vshiroky
3(x-2)^3+x When x=4 We got 28
UsukiDoll
  • UsukiDoll
|dw:1436328303921:dw|
vshiroky
  • vshiroky
-5y^3+6k when y=-2 and k=1 We got 46
UsukiDoll
  • UsukiDoll
|dw:1436328365051:dw|
vshiroky
  • vshiroky
|dw:1436328423858:dw|
vshiroky
  • vshiroky
x=9 and m=-3
vshiroky
  • vshiroky
we got 9
UsukiDoll
  • UsukiDoll
:/ I got multiple answers on this one.
UsukiDoll
  • UsukiDoll
|dw:1436328778177:dw|
nincompoop
  • nincompoop
use PEMDAS
UsukiDoll
  • UsukiDoll
PEMDAS will tell me to do parenthesis.. k check then I do multiplication.. now I need division.
vshiroky
  • vshiroky
We have like 5 more if that's ok
UsukiDoll
  • UsukiDoll
k that's fine.. it's easy enough.
vshiroky
  • vshiroky
6(h-3)^2+5v H=6 and v=-5 We got 29
UsukiDoll
  • UsukiDoll
|dw:1436328918849:dw| for the previous problem
vshiroky
  • vshiroky
|dw:1436328947288:dw|
UsukiDoll
  • UsukiDoll
|dw:1436328955660:dw|
UsukiDoll
  • UsukiDoll
I'm kind of delayed a bit xD
vshiroky
  • vshiroky
Srry lol
UsukiDoll
  • UsukiDoll
|dw:1436329045925:dw| anything to the 0 power will result in a 1. so for 6^0 since 6 is raised to the zero power, our result is just 1 The zero exponent rule basically says that any base with an exponent of zero is equal to one. For example: x^0 = 1
vshiroky
  • vshiroky
|dw:1436329245453:dw|
UsukiDoll
  • UsukiDoll
|dw:1436329313843:dw|
vshiroky
  • vshiroky
|dw:1436329393789:dw|
UsukiDoll
  • UsukiDoll
is it x = -2 or x = 2 ?
UsukiDoll
  • UsukiDoll
the = sign and - sign are squished together so it's hard to tell .
vshiroky
  • vshiroky
it's -2
UsukiDoll
  • UsukiDoll
|dw:1436329522740:dw| the negative sign being distributed for -(-8) cancels the negative it's similar to -1(-8) = 8 a negative times a negative is a positive.
UsukiDoll
  • UsukiDoll
if the x was 2, then the answer would be 2 -(2)^3+2(5) -8+10=2
vshiroky
  • vshiroky
I thought -2^3 was -8
UsukiDoll
  • UsukiDoll
I think it had something to do with the negative in front of -x^3 and since x = -2 we had -(-2)^3
UsukiDoll
  • UsukiDoll
-(-8) ->8
UsukiDoll
  • UsukiDoll
let me recheck on a calculator
vshiroky
  • vshiroky
Gotcha
UsukiDoll
  • UsukiDoll
if x = -2 http://www.wolframalpha.com/input/?i=-%28-2%29%5E3%2B2%285%29 if x = 2 http://www.wolframalpha.com/input/?i=-%282%29%5E3%2B2%285%29
vshiroky
  • vshiroky
|dw:1436329893072:dw|
UsukiDoll
  • UsukiDoll
|dw:1436329942432:dw|
vshiroky
  • vshiroky
|dw:1436329944652:dw|
UsukiDoll
  • UsukiDoll
uh oh... is r = -2 or r = 2 ?
vshiroky
  • vshiroky
|dw:1436329996706:dw|
UsukiDoll
  • UsukiDoll
r is confusing.. I gotta be honest it can go both ways.
vshiroky
  • vshiroky
|dw:1436330028192:dw|
vshiroky
  • vshiroky
Sorry I just sent I think the last 2
UsukiDoll
  • UsukiDoll
|dw:1436330096190:dw|
vshiroky
  • vshiroky
r is -2
UsukiDoll
  • UsukiDoll
|dw:1436330131414:dw|
vshiroky
  • vshiroky
oops theres a couple more
vshiroky
  • vshiroky
Can I type all 5 real quick? I have to run outside quickly
UsukiDoll
  • UsukiDoll
|dw:1436330190606:dw||dw:1436330281564:dw| yeah sure
vshiroky
  • vshiroky
|dw:1436330310576:dw|
vshiroky
  • vshiroky
|dw:1436330398457:dw|
vshiroky
  • vshiroky
|dw:1436330429068:dw|
vshiroky
  • vshiroky
|dw:1436330461718:dw|
vshiroky
  • vshiroky
|dw:1436330497051:dw|
UsukiDoll
  • UsukiDoll
|dw:1436330454834:dw||dw:1436330658029:dw||dw:1436330733880:dw||dw:1436330763180:dw||dw:1436330801972:dw|
UsukiDoll
  • UsukiDoll
SO far, the answers are wrong. It's not good to rush at math problems because there will be mistakes.
vshiroky
  • vshiroky
She did those in her class, I just wanted to double check them but didn't have a chance yet lol
UsukiDoll
  • UsukiDoll
oh I see xD
vshiroky
  • vshiroky
Thank you for all your help!!

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